Divide (3x^2-2xy)/(2x)

$\frac{3 x^{2} - 2 x y}{2 x}$

Step 1

Factor $x$ out of $3 x^{2} - 2 x y$ .

Factor $x$ out of $3 x^{2}$ .

$\frac{x (3 x) - 2 x y}{2 x}$

Factor $x$ out of $- 2 x y$ .

$\frac{x (3 x) + x (- 2 y)}{2 x}$

Factor $x$ out of $x (3 x) + x (- 2 y)$ .

$\frac{x (3 x - 2 y)}{2 x}$

$\frac{x (3 x - 2 y)}{2 x}$

Step 2

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{x (3 x - 2 y)}{2 x}$

Rewrite the expression.

$\frac{3 x - 2 y}{2}$

$\frac{3 x - 2 y}{2}$

Step 3

Split the fraction $\frac{3 x - 2 y}{2}$ into two fractions.

$\frac{3 x}{2} + \frac{- 2 y}{2}$

Step 4

Cancel the common factor of $- 2$ and $2$ .

Factor $2$ out of $- 2 y$ .

$\frac{3 x}{2} + \frac{2 (- y)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{3 x}{2} + \frac{2 (- y)}{2 (1)}$

Cancel the common factor.

$\frac{3 x}{2} + \frac{2 (- y)}{2 \cdot 1}$

Rewrite the expression.

$\frac{3 x}{2} + \frac{- y}{1}$

Divide $- y$ by $1$ .

$\frac{3 x}{2} - y$

$\frac{3 x}{2} - y$

$\frac{3 x}{2} - y$

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