Evaluate (4|-6|)/2+|-6-3|

$\frac{4 | - 6 |}{2} + | - 6 - 3 |$

Step 1

Simplify each term.

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $4 | - 6 |$ .

$\frac{2 (2 | - 6 |)}{2} + | - 6 - 3 |$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 (2 | - 6 |)}{2 (1)} + | - 6 - 3 |$

Cancel the common factor.

$\frac{2 (2 | - 6 |)}{2 \cdot 1} + | - 6 - 3 |$

Rewrite the expression.

$\frac{2 | - 6 |}{1} + | - 6 - 3 |$

Divide $2 | - 6 |$ by $1$ .

$2 | - 6 | + | - 6 - 3 |$

The absolute value is the distance between a number and zero. The distance between $- 6$ and $0$ is $6$ .

$2 \cdot 6 + | - 6 - 3 |$

Multiply $2$ by $6$ .

$12 + | - 6 - 3 |$

Subtract $3$ from $- 6$ .

$12 + | - 9 |$

The absolute value is the distance between a number and zero. The distance between $- 9$ and $0$ is $9$ .

$12 + 9$

Step 2

Add $12$ and $9$ .

$21$