Evaluate cube root of 2 cube root of 32

$\sqrt[3]{2} \sqrt[3]{32}$

Step 1

Combine using the product rule for radicals.

$\sqrt[3]{2 \cdot 32}$

Step 2

Simplify the expression.

Multiply $2$ by $32$ .

$\sqrt[3]{64}$

Rewrite $64$ as $4^{3}$ .

$\sqrt[3]{4^{3}}$

Pull terms out from under the radical, assuming real numbers.

$4$