Find the Excluded Values 1/(x+1)+5=11/(x+1)

$\frac{1}{x + 1} + 5 = \frac{11}{x + 1}$

Step 1

Subtract $\frac{11}{x + 1}$ from both sides of the equation.

$\frac{1}{x + 1} + 5 - \frac{11}{x + 1} = 0$

Step 2

Simplify $\frac{1}{x + 1} + 5 - \frac{11}{x + 1}$ .

Combine the numerators over the common denominator.

$5 + \frac{1 - 11}{x + 1} = 0$

Subtract $11$ from $1$ .

$5 + \frac{- 10}{x + 1} = 0$

Move the negative in front of the fraction.

$5 - \frac{10}{x + 1} = 0$

To write $5$ as a fraction with a common denominator, multiply by $\frac{x + 1}{x + 1}$ .

$\frac{5 (x + 1)}{x + 1} - \frac{10}{x + 1} = 0$

Combine the numerators over the common denominator.

$\frac{5 (x + 1) - 10}{x + 1} = 0$

Simplify the numerator.

Factor $5$ out of $5 (x + 1) - 10$ .

Factor $5$ out of $- 10$ .

$\frac{5 (x + 1) + 5 \cdot - 2}{x + 1} = 0$

Factor $5$ out of $5 (x + 1) + 5 \cdot - 2$ .

$\frac{5 (x + 1 - 2)}{x + 1} = 0$

Subtract $2$ from $1$ .

$\frac{5 (x - 1)}{x + 1} = 0$

Step 3

Set the denominator in $\frac{5 (x - 1)}{x + 1}$ equal to $0$ to find where the expression is undefined.

$x + 1 = 0$

Step 4

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 5