Find the First Term a_n=3(2)^(n-1)

$a_{n} = 3 {(2)}^{n - 1}$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$a_{1} = 3 {(2)}^{(1) - 1}$

Step 2

Subtract $1$ from $1$ .

$a_{1} = 3 \cdot 2^{0}$

Step 3

Anything raised to $0$ is $1$ .

$a_{1} = 3 \cdot 1$

Step 4

Multiply $3$ by $1$ .

$a_{1} = 3$