Find the Mean 12 , 17 , 16 , 10 , 20 , 13 , 14 , 14 , 12 , 12 , 19 , 18

$12$ , $17$ , $16$ , $10$ , $20$ , $13$ , $14$ , $14$ , $12$ , $12$ , $19$ , $18$

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{12 + 17 + 16 + 10 + 20 + 13 + 14 + 14 + 12 + 12 + 19 + 18}{12}$

Simplify the numerator.

Add $12$ and $17$ .

$\frac{29 + 16 + 10 + 20 + 13 + 14 + 14 + 12 + 12 + 19 + 18}{12}$

Add $29$ and $16$ .

$\frac{45 + 10 + 20 + 13 + 14 + 14 + 12 + 12 + 19 + 18}{12}$

Add $45$ and $10$ .

$\frac{55 + 20 + 13 + 14 + 14 + 12 + 12 + 19 + 18}{12}$

Add $55$ and $20$ .

$\frac{75 + 13 + 14 + 14 + 12 + 12 + 19 + 18}{12}$

Add $75$ and $13$ .

$\frac{88 + 14 + 14 + 12 + 12 + 19 + 18}{12}$

Add $88$ and $14$ .

$\frac{102 + 14 + 12 + 12 + 19 + 18}{12}$

Add $102$ and $14$ .

$\frac{116 + 12 + 12 + 19 + 18}{12}$

Add $116$ and $12$ .

$\frac{128 + 12 + 19 + 18}{12}$

Add $128$ and $12$ .

$\frac{140 + 19 + 18}{12}$

Add $140$ and $19$ .

$\frac{159 + 18}{12}$

Add $159$ and $18$ .

$\frac{177}{12}$

Cancel the common factor of $177$ and $12$ .

Factor $3$ out of $177$ .

$\frac{3 (59)}{12}$

Cancel the common factors.

Factor $3$ out of $12$ .

$\frac{3 \cdot 59}{3 \cdot 4}$

Cancel the common factor.

$\frac{3 \cdot 59}{3 \cdot 4}$

Rewrite the expression.

$\frac{59}{4}$

Divide.

$14.75$

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$14.8$

Find the Mean 12 , 17 , 16 , 10 , 20 , 13 , 14 , 14 , 12 , 12 , 19 , 18

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