Find the Mean 6 , 12 , 24 , 48

$6$ , $12$ , $24$ , $48$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{6 + 12 + 24 + 48}{4}$

Step 2

Cancel the common factor of $6 + 12 + 24 + 48$ and $4$ .

Factor $2$ out of $6$ .

$\frac{2 (3) + 12 + 24 + 48}{4}$

Factor $2$ out of $12$ .

$\frac{2 \cdot 3 + 2 \cdot 6 + 24 + 48}{4}$

Factor $2$ out of $2 \cdot 3 + 2 \cdot 6$ .

$\frac{2 \cdot (3 + 6) + 24 + 48}{4}$

Factor $2$ out of $24$ .

$\frac{2 \cdot (3 + 6) + 2 (12) + 48}{4}$

Factor $2$ out of $2 \cdot (3 + 6) + 2 (12)$ .

$\frac{2 \cdot (3 + 6 + 12) + 48}{4}$

Factor $2$ out of $48$ .

$\frac{2 \cdot (3 + 6 + 12) + 2 (24)}{4}$

Factor $2$ out of $2 \cdot (3 + 6 + 12) + 2 (24)$ .

$\frac{2 \cdot (3 + 6 + 12 + 24)}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$\frac{2 \cdot (3 + 6 + 12 + 24)}{2 (2)}$

Cancel the common factor.

$\frac{2 \cdot (3 + 6 + 12 + 24)}{2 \cdot 2}$

Rewrite the expression.

$\frac{3 + 6 + 12 + 24}{2}$

Step 3

Simplify the numerator.

Add $3$ and $6$ .

$\frac{9 + 12 + 24}{2}$

Add $9$ and $12$ .

$\frac{21 + 24}{2}$

Add $21$ and $24$ .

$\frac{45}{2}$

Step 4

Divide.

$22.5$