Find the Oxidation Numbers Fe_2O_2

$F e_{2} O_{2}$

Step 1

Since $F e$ is in column $3$ of the periodic table, it will share $3$ electrons and use an oxidation state of $3$ .

$F e = 2 (3) = 6$

Step 2

Since $O$ is in column $6$ of the periodic table, it will share $6$ electrons and use an oxidation state of $6$ .

$O = 2 (- 2) = - 4$

Step 3

This is the full list of oxidation states for this molecule.

$F e = 6, O = - 4$