Find the Points of Intersection 2x+y=0 y=3

$2 x + y = 0$ $y = 3$

Replace all occurrences of $y$ with $3$ in each equation.

Replace all occurrences of $y$ in $2 x + y = 0$ with $3$ .

$2 x + 3 = 0$

$y = 3$

Simplify the left side.

Remove parentheses.

$2 x + 3 = 0$

$y = 3$

$2 x + 3 = 0$

$y = 3$

$2 x + 3 = 0$

$y = 3$

Solve for $x$ in $2 x + 3 = 0$ .

Subtract $3$ from both sides of the equation.

$2 x = - 3$

$y = 3$

Divide each term in $2 x = - 3$ by $2$ and simplify.

Divide each term in $2 x = - 3$ by $2$ .

$\frac{2 x}{2} = \frac{- 3}{2}$

$y = 3$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 3}{2}$

$y = 3$

Divide $x$ by $1$ .

$x = \frac{- 3}{2}$

$y = 3$

$x = \frac{- 3}{2}$

$y = 3$

$x = \frac{- 3}{2}$

$y = 3$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{3}{2}$

$y = 3$

$x = - \frac{3}{2}$

$y = 3$

$x = - \frac{3}{2}$

$y = 3$

$x = - \frac{3}{2}$

$y = 3$

Solve the system of equations $x = - \frac{3}{2} y = 3$ .

$x = - \frac{3}{2} y = 3$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- \frac{3}{2}, 3)$

The result can be shown in multiple forms.

Point Form:

$(- \frac{3}{2}, 3)$

Equation Form:

$x = - \frac{3}{2}, y = 3$

Find the Points of Intersection 2x+y=0 y=3

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