Find Three Ordered Pair Solutions y+2x=8

$y + 2 x = 8$

Step 1

Subtract $2 x$ from both sides of the equation.

$y = 8 - 2 x$

Step 2

Choose any value for $x$ that is in the domain to plug into the equation.

Step 3

Choose $0$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 8 - 2 \cdot 0$

Simplify $8 - 2 \cdot 0$ .

Multiply $- 2$ by $0$ .

$y = 8 + 0$

Add $8$ and $0$ .

$y = 8$

Use the $x$ and $y$ values to form the ordered pair.

$(0, 8)$

Step 4

Choose $1$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 8 - 2 \cdot 1$

Simplify $8 - 2 \cdot 1$ .

Multiply $- 2$ by $1$ .

$y = 8 - 2$

Subtract $2$ from $8$ .

$y = 6$

Use the $x$ and $y$ values to form the ordered pair.

$(1, 6)$

Step 5

Choose $2$ to substitute in for $x$ to find the ordered pair.

Remove parentheses.

$y = 8 - 2 \cdot 2$

Simplify $8 - 2 \cdot 2$ .

Multiply $- 2$ by $2$ .

$y = 8 - 4$

Subtract $4$ from $8$ .

$y = 4$

Use the $x$ and $y$ values to form the ordered pair.

$(2, 4)$

Step 6

These are three possible solutions to the equation.

$(0, 8), (1, 6), (2, 4)$

Step 7