Find Where Undefined/Discontinuous f(x)=(4x^2-16)/(2x-4)

$f (x) = \frac{4 x^{2} - 16}{2 x - 4}$

Step 1

Set the denominator in $\frac{4 x^{2} - 16}{2 x - 4}$ equal to $0$ to find where the expression is undefined.

$2 x - 4 = 0$

Step 2

Solve for $x$ .

Add $4$ to both sides of the equation.

$2 x = 4$

Divide each term in $2 x = 4$ by $2$ and simplify.

Divide each term in $2 x = 4$ by $2$ .

$\frac{2 x}{2} = \frac{4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{4}{2}$

Divide $x$ by $1$ .

$x = \frac{4}{2}$

Simplify the right side.

Divide $4$ by $2$ .

$x = 2$

Step 3