Graph 7<x+3y

$7 < x + 3 y$

Step 1

Write in $y = m x + b$ form.

Solve for $y$ .

Rewrite so $y$ is on the left side of the inequality.

$x + 3 y > 7$

Subtract $x$ from both sides of the inequality.

$3 y > 7 - x$

Divide each term in $3 y > 7 - x$ by $3$ and simplify.

Divide each term in $3 y > 7 - x$ by $3$ .

$\frac{3 y}{3} > \frac{7}{3} + \frac{- x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} > \frac{7}{3} + \frac{- x}{3}$

Divide $y$ by $1$ .

$y > \frac{7}{3} + \frac{- x}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$y > \frac{7}{3} - \frac{x}{3}$

Rearrange terms.

$y > - \frac{x}{3} + \frac{7}{3}$

Reorder terms.

$y > - (\frac{1}{3} x) + \frac{7}{3}$

Remove parentheses.

$y > - \frac{1}{3} x + \frac{7}{3}$

Step 2

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - \frac{1}{3}$

$b = \frac{7}{3}$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- \frac{1}{3}$

y-intercept: $(0, \frac{7}{3})$

Slope: $- \frac{1}{3}$

y-intercept: $(0, \frac{7}{3})$

Step 3

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $- \frac{1}{3} x + \frac{7}{3}$ .

$y > - \frac{1}{3} x + \frac{7}{3}$

Step 4