Graph 8y>-10x+24 y<=2

$8 y > - 10 x + 24$ $y \leq 2$

Graph $8 y > - 10 x + 24$ .

Write in $y = m x + b$ form.

Divide each term in $8 y > - 10 x + 24$ by $8$ and simplify.

Divide each term in $8 y > - 10 x + 24$ by $8$ .

$\frac{8 y}{8} > \frac{- 10 x}{8} + \frac{24}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 y}{8} > \frac{- 10 x}{8} + \frac{24}{8}$

Divide $y$ by $1$ .

$y > \frac{- 10 x}{8} + \frac{24}{8}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 10$ and $8$ .

Factor $2$ out of $- 10 x$ .

$y > \frac{2 (- 5 x)}{8} + \frac{24}{8}$

Cancel the common factors.

Factor $2$ out of $8$ .

$y > \frac{2 (- 5 x)}{2 (4)} + \frac{24}{8}$

Cancel the common factor.

$y > \frac{2 (- 5 x)}{2 \cdot 4} + \frac{24}{8}$

Rewrite the expression.

$y > \frac{- 5 x}{4} + \frac{24}{8}$

Move the negative in front of the fraction.

$y > - \frac{(5) x}{4} + \frac{24}{8}$

Divide $24$ by $8$ .

$y > - \frac{5 x}{4} + 3$

Reorder terms.

$y > - (\frac{5}{4} x) + 3$

Remove parentheses.

$y > - \frac{5}{4} x + 3$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - \frac{5}{4}$

$b = 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- \frac{5}{4}$

y-intercept: $(0, 3)$

Slope: $- \frac{5}{4}$

y-intercept: $(0, 3)$

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $- \frac{5}{4} x + 3$ .

$y > - \frac{5}{4} x + 3$

Graph $y \leq 2$ .

$y \leq 2$

Plot each graph on the same coordinate system.

$8 y > - 10 x + 24$

$y \leq 2$

Graph 8y>-10x+24 y<=2

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