Graph Using a Table of Values g(x)=7^x

$g (x) = 7^{x}$

Step 1

Substitute $- 2$ for $x$ and find the result for $y$ .

$y = 7^{- 2}$

Step 2

Simplify $7^{- 2}$ .

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$y = \frac{1}{7^{2}}$

Raise $7$ to the power of $2$ .

$y = \frac{1}{49}$

Step 3

Substitute $- 1$ for $x$ and find the result for $y$ .

$y = 7^{- 1}$

Step 4

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$y = \frac{1}{7}$

Step 5

Substitute $0$ for $x$ and find the result for $y$ .

$y = 7^{0}$

Step 6

Anything raised to $0$ is $1$ .

$y = 1$

Step 7

Substitute $1$ for $x$ and find the result for $y$ .

$y = 7^{1}$

Step 8

Evaluate the exponent.

$y = 7$

Step 9

Substitute $2$ for $x$ and find the result for $y$ .

$y = 7^{2}$

Step 10

Raise $7$ to the power of $2$ .

$y = 49$

Step 11

This is a table of possible values to use when graphing the equation.

$\begin{array}{c} x & y \\ - 2 & \frac{1}{49} \\ - 1 & \frac{1}{7} \\ 0 & 1 \\ 1 & 7 \\ 2 & 49 \end{array}$

Step 12