Graph y<=1/7x-6 y<=9/7x+2

$y \leq \frac{1}{7} x - 6$ $y \leq \frac{9}{7} x + 2$

Graph $y \leq \frac{1}{7} x - 6$ .

Find the slope and the y-intercept for the boundary line.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Combine $\frac{1}{7}$ and $x$ .

$y \leq \frac{x}{7} - 6$

Reorder terms.

$y \leq \frac{1}{7} x - 6$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{7}$

$b = - 6$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{7}$

y-intercept: $(0, - 6)$

Slope: $\frac{1}{7}$

y-intercept: $(0, - 6)$

Slope: $\frac{1}{7}$

y-intercept: $(0, - 6)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $\frac{1}{7} x - 6$ .

$y \leq \frac{1}{7} x - 6$

Graph $y \leq \frac{9}{7} x + 2$ .

Find the slope and the y-intercept for the boundary line.

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Simplify the right side.

Combine $\frac{9}{7}$ and $x$ .

$y \leq \frac{9 x}{7} + 2$

Reorder terms.

$y \leq \frac{9}{7} x + 2$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{9}{7}$

$b = 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{9}{7}$

y-intercept: $(0, 2)$

Slope: $\frac{9}{7}$

y-intercept: $(0, 2)$

Slope: $\frac{9}{7}$

y-intercept: $(0, 2)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $\frac{9}{7} x + 2$ .

$y \leq \frac{9}{7} x + 2$

Plot each graph on the same coordinate system.

$y \leq \frac{1}{7} x - 6$

$y \leq \frac{9}{7} x + 2$

Graph y<=1/7x-6 y<=9/7x+2

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