Graph y>=x^2-49 x-y>=-7

$y \geq x^{2} - 49$ $x - y \geq - 7$

Graph $y \geq x^{2} - 49$ .

The equation is not linear, so a constant slope does not exist.

Not Linear

Graph a solid line, then shade the area above the boundary line since $y$ is greater than $x^{2} - 49$ .

$y \geq x^{2} - 49$

Graph $x - y \geq - 7$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Subtract $x$ from both sides of the inequality.

$- y \geq - 7 - x$

Divide each term in $- y \geq - 7 - x$ by $- 1$ and simplify.

Divide each term in $- y \geq - 7 - x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} \leq \frac{- 7}{- 1} + \frac{- x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} \leq \frac{- 7}{- 1} + \frac{- x}{- 1}$

Divide $y$ by $1$ .

$y \leq \frac{- 7}{- 1} + \frac{- x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $- 7$ by $- 1$ .

$y \leq 7 + \frac{- x}{- 1}$

Dividing two negative values results in a positive value.

$y \leq 7 + \frac{x}{1}$

Divide $x$ by $1$ .

$y \leq 7 + x$

Rearrange terms.

$y \leq x + 7$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = 1$

$b = 7$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $1$

y-intercept: $(0, 7)$

Slope: $1$

y-intercept: $(0, 7)$

Graph a solid line, then shade the area below the boundary line since $y$ is less than $x + 7$ .

$y \leq x + 7$

Plot each graph on the same coordinate system.

$y \geq x^{2} - 49$

$x - y \geq - 7$

Graph y>=x^2-49 x-y>=-7

Related Questions

Support LCMGCF.com by disabling your adblocker.