Solve by Factoring 27x^3=8

$27 x^{3} = 8$

Step 1

Subtract $8$ from both sides of the equation.

$27 x^{3} - 8 = 0$

Step 2

Rewrite $27 x^{3}$ as ${(3 x)}^{3}$ .

${(3 x)}^{3} - 8 = 0$

Step 3

Rewrite $8$ as $2^{3}$ .

${(3 x)}^{3} - 2^{3} = 0$

Step 4

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 3 x$ and $b = 2$ .

$(3 x - 2) ({(3 x)}^{2} + 3 x \cdot 2 + 2^{2}) = 0$

Step 5

Simplify.

Apply the product rule to $3 x$ .

$(3 x - 2) (3^{2} x^{2} + 3 x \cdot 2 + 2^{2}) = 0$

Raise $3$ to the power of $2$ .

$(3 x - 2) (9 x^{2} + 3 x \cdot 2 + 2^{2}) = 0$

Multiply $2$ by $3$ .

$(3 x - 2) (9 x^{2} + 6 x + 2^{2}) = 0$

Raise $2$ to the power of $2$ .

$(3 x - 2) (9 x^{2} + 6 x + 4) = 0$

Step 6

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$3 x - 2 = 0$

$9 x^{2} + 6 x + 4 = 0$

Step 7

Set $3 x - 2$ equal to $0$ and solve for $x$ .

Set $3 x - 2$ equal to $0$ .

$3 x - 2 = 0$

Solve $3 x - 2 = 0$ for $x$ .

Add $2$ to both sides of the equation.

$3 x = 2$

Divide each term in $3 x = 2$ by $3$ and simplify.

Divide each term in $3 x = 2$ by $3$ .

$\frac{3 x}{3} = \frac{2}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{2}{3}$

Divide $x$ by $1$ .

$x = \frac{2}{3}$

Step 8

Set $9 x^{2} + 6 x + 4$ equal to $0$ and solve for $x$ .

Set $9 x^{2} + 6 x + 4$ equal to $0$ .

$9 x^{2} + 6 x + 4 = 0$

Solve $9 x^{2} + 6 x + 4 = 0$ for $x$ .

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 9$ , $b = 6$ , and $c = 4$ into the quadratic formula and solve for $x$ .

$\frac{- 6 \pm \sqrt{6^{2} - 4 \cdot (9 \cdot 4)}}{2 \cdot 9}$

Simplify.

Simplify the numerator.

Raise $6$ to the power of $2$ .

$x = \frac{- 6 \pm \sqrt{36 - 4 \cdot 9 \cdot 4}}{2 \cdot 9}$

Multiply $- 4 \cdot 9 \cdot 4$ .

Multiply $- 4$ by $9$ .

$x = \frac{- 6 \pm \sqrt{36 - 36 \cdot 4}}{2 \cdot 9}$

Multiply $- 36$ by $4$ .

$x = \frac{- 6 \pm \sqrt{36 - 144}}{2 \cdot 9}$

Subtract $144$ from $36$ .

$x = \frac{- 6 \pm \sqrt{- 108}}{2 \cdot 9}$

Rewrite $- 108$ as $- 1 (108)$ .

$x = \frac{- 6 \pm \sqrt{- 1 \cdot 108}}{2 \cdot 9}$

Rewrite $\sqrt{- 1 (108)}$ as $\sqrt{- 1} \cdot \sqrt{108}$ .

$x = \frac{- 6 \pm \sqrt{- 1} \cdot \sqrt{108}}{2 \cdot 9}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{- 6 \pm i \cdot \sqrt{108}}{2 \cdot 9}$

Rewrite $108$ as $6^{2} \cdot 3$ .

Factor $36$ out of $108$ .

$x = \frac{- 6 \pm i \cdot \sqrt{36 (3)}}{2 \cdot 9}$

Rewrite $36$ as $6^{2}$ .

$x = \frac{- 6 \pm i \cdot \sqrt{6^{2} \cdot 3}}{2 \cdot 9}$

Pull terms out from under the radical.

$x = \frac{- 6 \pm i \cdot (6 \sqrt{3})}{2 \cdot 9}$

Move $6$ to the left of $i$ .

$x = \frac{- 6 \pm 6 i \sqrt{3}}{2 \cdot 9}$

Multiply $2$ by $9$ .

$x = \frac{- 6 \pm 6 i \sqrt{3}}{18}$

Simplify $\frac{- 6 \pm 6 i \sqrt{3}}{18}$ .

$x = \frac{- 1 \pm i \sqrt{3}}{3}$

Simplify the expression to solve for the $+$ portion of the $\pm$ .

Simplify the numerator.

Raise $6$ to the power of $2$ .

$x = \frac{- 6 \pm \sqrt{36 - 4 \cdot 9 \cdot 4}}{2 \cdot 9}$

Multiply $- 4 \cdot 9 \cdot 4$ .

Multiply $- 4$ by $9$ .

$x = \frac{- 6 \pm \sqrt{36 - 36 \cdot 4}}{2 \cdot 9}$

Multiply $- 36$ by $4$ .

$x = \frac{- 6 \pm \sqrt{36 - 144}}{2 \cdot 9}$

Subtract $144$ from $36$ .

$x = \frac{- 6 \pm \sqrt{- 108}}{2 \cdot 9}$

Rewrite $- 108$ as $- 1 (108)$ .

$x = \frac{- 6 \pm \sqrt{- 1 \cdot 108}}{2 \cdot 9}$

Rewrite $\sqrt{- 1 (108)}$ as $\sqrt{- 1} \cdot \sqrt{108}$ .

$x = \frac{- 6 \pm \sqrt{- 1} \cdot \sqrt{108}}{2 \cdot 9}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{- 6 \pm i \cdot \sqrt{108}}{2 \cdot 9}$

Rewrite $108$ as $6^{2} \cdot 3$ .

Factor $36$ out of $108$ .

$x = \frac{- 6 \pm i \cdot \sqrt{36 (3)}}{2 \cdot 9}$

Rewrite $36$ as $6^{2}$ .

$x = \frac{- 6 \pm i \cdot \sqrt{6^{2} \cdot 3}}{2 \cdot 9}$

Pull terms out from under the radical.

$x = \frac{- 6 \pm i \cdot (6 \sqrt{3})}{2 \cdot 9}$

Move $6$ to the left of $i$ .

$x = \frac{- 6 \pm 6 i \sqrt{3}}{2 \cdot 9}$

Multiply $2$ by $9$ .

$x = \frac{- 6 \pm 6 i \sqrt{3}}{18}$

Simplify $\frac{- 6 \pm 6 i \sqrt{3}}{18}$ .

$x = \frac{- 1 \pm i \sqrt{3}}{3}$

Change the $\pm$ to $+$ .

$x = \frac{- 1 + i \sqrt{3}}{3}$

Rewrite $- 1$ as $- 1 (1)$ .

$x = \frac{- 1 \cdot 1 + i \sqrt{3}}{3}$

Factor $- 1$ out of $i \sqrt{3}$ .

$x = \frac{- 1 \cdot 1 - (- i \sqrt{3})}{3}$

Factor $- 1$ out of $- 1 (1) - (- i \sqrt{3})$ .

$x = \frac{- 1 (1 - i \sqrt{3})}{3}$

Move the negative in front of the fraction.

$x = - \frac{1 - i \sqrt{3}}{3}$

Simplify the expression to solve for the $-$ portion of the $\pm$ .

Simplify the numerator.

Raise $6$ to the power of $2$ .

$x = \frac{- 6 \pm \sqrt{36 - 4 \cdot 9 \cdot 4}}{2 \cdot 9}$

Multiply $- 4 \cdot 9 \cdot 4$ .

Multiply $- 4$ by $9$ .

$x = \frac{- 6 \pm \sqrt{36 - 36 \cdot 4}}{2 \cdot 9}$

Multiply $- 36$ by $4$ .

$x = \frac{- 6 \pm \sqrt{36 - 144}}{2 \cdot 9}$

Subtract $144$ from $36$ .

$x = \frac{- 6 \pm \sqrt{- 108}}{2 \cdot 9}$

Rewrite $- 108$ as $- 1 (108)$ .

$x = \frac{- 6 \pm \sqrt{- 1 \cdot 108}}{2 \cdot 9}$

Rewrite $\sqrt{- 1 (108)}$ as $\sqrt{- 1} \cdot \sqrt{108}$ .

$x = \frac{- 6 \pm \sqrt{- 1} \cdot \sqrt{108}}{2 \cdot 9}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{- 6 \pm i \cdot \sqrt{108}}{2 \cdot 9}$

Rewrite $108$ as $6^{2} \cdot 3$ .

Factor $36$ out of $108$ .

$x = \frac{- 6 \pm i \cdot \sqrt{36 (3)}}{2 \cdot 9}$

Rewrite $36$ as $6^{2}$ .

$x = \frac{- 6 \pm i \cdot \sqrt{6^{2} \cdot 3}}{2 \cdot 9}$

Pull terms out from under the radical.

$x = \frac{- 6 \pm i \cdot (6 \sqrt{3})}{2 \cdot 9}$

Move $6$ to the left of $i$ .

$x = \frac{- 6 \pm 6 i \sqrt{3}}{2 \cdot 9}$

Multiply $2$ by $9$ .

$x = \frac{- 6 \pm 6 i \sqrt{3}}{18}$

Simplify $\frac{- 6 \pm 6 i \sqrt{3}}{18}$ .

$x = \frac{- 1 \pm i \sqrt{3}}{3}$

Change the $\pm$ to $-$ .

$x = \frac{- 1 - i \sqrt{3}}{3}$

Rewrite $- 1$ as $- 1 (1)$ .

$x = \frac{- 1 \cdot 1 - i \sqrt{3}}{3}$

Factor $- 1$ out of $- i \sqrt{3}$ .

$x = \frac{- 1 \cdot 1 - (i \sqrt{3})}{3}$

Factor $- 1$ out of $- 1 (1) - (i \sqrt{3})$ .

$x = \frac{- 1 (1 + i \sqrt{3})}{3}$

Move the negative in front of the fraction.

$x = - \frac{1 + i \sqrt{3}}{3}$

The final answer is the combination of both solutions.

$x = - \frac{1 - i \sqrt{3}}{3}, - \frac{1 + i \sqrt{3}}{3}$

Step 9

The final solution is all the values that make $(3 x - 2) (9 x^{2} + 6 x + 4) = 0$ true.

$x = \frac{2}{3}, - \frac{1 - i \sqrt{3}}{3}, - \frac{1 + i \sqrt{3}}{3}$

Solve by Factoring 27x^3=8

Related Questions

Support LCMGCF.com by disabling your adblocker.