Solve by Graphing 4x-2y=-8 , y=-2x+4

$4 x - 2 y = - 8$ , $y = - 2 x + 4$

Step 1

Subtract $4 x$ from both sides of the equation.

$- 2 y = - 8 - 4 x$

$y = - 2 x + 4$

Step 2

Divide each term in $- 2 y = - 8 - 4 x$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 8 - 4 x$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 8}{- 2} + \frac{- 4 x}{- 2}$

$y = - 2 x + 4$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 8}{- 2} + \frac{- 4 x}{- 2}$

$y = - 2 x + 4$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 2} + \frac{- 4 x}{- 2}$

$y = - 2 x + 4$

$y = \frac{- 8}{- 2} + \frac{- 4 x}{- 2}$

$y = - 2 x + 4$

$y = \frac{- 8}{- 2} + \frac{- 4 x}{- 2}$

$y = - 2 x + 4$

Simplify the right side.

Simplify each term.

Divide $- 8$ by $- 2$ .

$y = 4 + \frac{- 4 x}{- 2}$

$y = - 2 x + 4$

Cancel the common factor of $- 4$ and $- 2$ .

Factor $- 2$ out of $- 4 x$ .

$y = 4 + \frac{- 2 (2 x)}{- 2}$

$y = - 2 x + 4$

Cancel the common factors.

Factor $- 2$ out of $- 2$ .

$y = 4 + \frac{- 2 (2 x)}{- 2 \cdot 1}$

$y = - 2 x + 4$

Cancel the common factor.

$y = 4 + \frac{- 2 (2 x)}{- 2 \cdot 1}$

$y = - 2 x + 4$

Rewrite the expression.

$y = 4 + \frac{2 x}{1}$

$y = - 2 x + 4$

Divide $2 x$ by $1$ .

$y = 4 + 2 x$

$y = - 2 x + 4$

$y = 4 + 2 x$

$y = - 2 x + 4$

$y = 4 + 2 x$

$y = - 2 x + 4$

$y = 4 + 2 x$

$y = - 2 x + 4$

$y = 4 + 2 x$

$y = - 2 x + 4$

$y = 4 + 2 x$

$y = - 2 x + 4$

Step 3

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(0, 4)$

Step 4

Solve by Graphing 4x-2y=-8 , y=-2x+4

Related Questions

Support LCMGCF.com by disabling your adblocker.