Solve by Graphing -4x+3y=-12 -2x+3y=-18

$- 4 x + 3 y = - 12$ $- 2 x + 3 y = - 18$

Step 1

Add $4 x$ to both sides of the equation.

$3 y = - 12 + 4 x$

$- 2 x + 3 y = - 18$

Step 2

Divide each term in $3 y = - 12 + 4 x$ by $3$ and simplify.

Divide each term in $3 y = - 12 + 4 x$ by $3$ .

$\frac{3 y}{3} = \frac{- 12}{3} + \frac{4 x}{3}$

$- 2 x + 3 y = - 18$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 12}{3} + \frac{4 x}{3}$

$- 2 x + 3 y = - 18$

Divide $y$ by $1$ .

$y = \frac{- 12}{3} + \frac{4 x}{3}$

$- 2 x + 3 y = - 18$

$y = \frac{- 12}{3} + \frac{4 x}{3}$

$- 2 x + 3 y = - 18$

$y = \frac{- 12}{3} + \frac{4 x}{3}$

$- 2 x + 3 y = - 18$

Simplify the right side.

Divide $- 12$ by $3$ .

$y = - 4 + \frac{4 x}{3}$

$- 2 x + 3 y = - 18$

$y = - 4 + \frac{4 x}{3}$

$- 2 x + 3 y = - 18$

$y = - 4 + \frac{4 x}{3}$

$- 2 x + 3 y = - 18$

Step 3

Add $2 x$ to both sides of the equation.

$3 y = - 18 + 2 x$

$y = - 4 + \frac{4 x}{3}$

Step 4

Divide each term in $3 y = - 18 + 2 x$ by $3$ and simplify.

Divide each term in $3 y = - 18 + 2 x$ by $3$ .

$\frac{3 y}{3} = \frac{- 18}{3} + \frac{2 x}{3}$

$y = - 4 + \frac{4 x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 18}{3} + \frac{2 x}{3}$

$y = - 4 + \frac{4 x}{3}$

Divide $y$ by $1$ .

$y = \frac{- 18}{3} + \frac{2 x}{3}$

$y = - 4 + \frac{4 x}{3}$

$y = \frac{- 18}{3} + \frac{2 x}{3}$

$y = - 4 + \frac{4 x}{3}$

$y = \frac{- 18}{3} + \frac{2 x}{3}$

$y = - 4 + \frac{4 x}{3}$

Simplify the right side.

Divide $- 18$ by $3$ .

$y = - 6 + \frac{2 x}{3}$

$y = - 4 + \frac{4 x}{3}$

$y = - 6 + \frac{2 x}{3}$

$y = - 4 + \frac{4 x}{3}$

$y = - 6 + \frac{2 x}{3}$

$y = - 4 + \frac{4 x}{3}$

Step 5

Create a graph to locate the intersection of the equations. The intersection of the system of equations is the solution.

$(- 3, - 8)$

Step 6

Solve by Graphing -4x+3y=-12 -2x+3y=-18

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