Solve by Substitution y=x-1 2x-y=0

$y = x - 1$ $2 x - y = 0$

Step 1

Replace all occurrences of $y$ with $x - 1$ in each equation.

Replace all occurrences of $y$ in $2 x - y = 0$ with $x - 1$ .

$2 x - (x - 1) = 0$

$y = x - 1$

Simplify the left side.

Simplify $2 x - (x - 1)$ .

Simplify each term.

Apply the distributive property.

$2 x - x + 1 = 0$

$y = x - 1$

Multiply $- 1$ by $- 1$ .

$2 x - x + 1 = 0$

$y = x - 1$

$2 x - x + 1 = 0$

$y = x - 1$

Subtract $x$ from $2 x$ .

$x + 1 = 0$

$y = x - 1$

$x + 1 = 0$

$y = x - 1$

$x + 1 = 0$

$y = x - 1$

$x + 1 = 0$

$y = x - 1$

Step 2

Subtract $1$ from both sides of the equation.

$x = - 1$

$y = x - 1$

Step 3

Replace all occurrences of $x$ with $- 1$ in each equation.

Replace all occurrences of $x$ in $y = x - 1$ with $- 1$ .

$y = (- 1) - 1$

$x = - 1$

Simplify the right side.

Subtract $1$ from $- 1$ .

$y = - 2$

$x = - 1$

$y = - 2$

$x = - 1$

$y = - 2$

$x = - 1$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 1, - 2)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(- 1, - 2)$

Equation Form:

$x = - 1, y = - 2$

Step 6

Solve by Substitution y=x-1 2x-y=0

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