Solve for A y=-Ax+8

$y = - A x + 8$

Step 1

Rewrite the equation as $- A x + 8 = y$ .

$- A x + 8 = y$

Step 2

Subtract $8$ from both sides of the equation.

$- A x = y - 8$

Step 3

Divide each term in $- A x = y - 8$ by $- 1 x$ and simplify.

Divide each term in $- A x = y - 8$ by $- 1 x$ .

$\frac{- A x}{- 1 x} = \frac{y}{- 1 x} + \frac{- 8}{- 1 x}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{A x}{x} = \frac{y}{- 1 x} + \frac{- 8}{- 1 x}$

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{A x}{x} = \frac{y}{- 1 x} + \frac{- 8}{- 1 x}$

Divide $A$ by $1$ .

$A = \frac{y}{- 1 x} + \frac{- 8}{- 1 x}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$A = - \frac{y}{x} + \frac{- 8}{- 1 x}$

Dividing two negative values results in a positive value.

$A = - \frac{y}{x} + \frac{8}{x}$