Solve for p 3(1+px)=12x

$3 (1 + p x) = 12 x$

Divide each term in $3 (1 + p x) = 12 x$ by $3$ and simplify.

Divide each term in $3 (1 + p x) = 12 x$ by $3$ .

$\frac{3 (1 + p x)}{3} = \frac{12 x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (1 + p x)}{3} = \frac{12 x}{3}$

Divide $1 + p x$ by $1$ .

$1 + p x = \frac{12 x}{3}$

Simplify the right side.

Cancel the common factor of $12$ and $3$ .

Factor $3$ out of $12 x$ .

$1 + p x = \frac{3 (4 x)}{3}$

Cancel the common factors.

Factor $3$ out of $3$ .

$1 + p x = \frac{3 (4 x)}{3 (1)}$

Cancel the common factor.

$1 + p x = \frac{3 (4 x)}{3 \cdot 1}$

Rewrite the expression.

$1 + p x = \frac{4 x}{1}$

Divide $4 x$ by $1$ .

$1 + p x = 4 x$

Subtract $1$ from both sides of the equation.

$p x = 4 x - 1$

Divide each term in $p x = 4 x - 1$ by $x$ and simplify.

Divide each term in $p x = 4 x - 1$ by $x$ .

$\frac{p x}{x} = \frac{4 x}{x} + \frac{- 1}{x}$

Simplify the left side.

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{p x}{x} = \frac{4 x}{x} + \frac{- 1}{x}$

Divide $p$ by $1$ .

$p = \frac{4 x}{x} + \frac{- 1}{x}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $x$ .

Cancel the common factor.

$p = \frac{4 x}{x} + \frac{- 1}{x}$

Divide $4$ by $1$ .

$p = 4 + \frac{- 1}{x}$

Move the negative in front of the fraction.

$p = 4 - \frac{1}{x}$