Solve for x -1/4x-12=x+3

$- \frac{1}{4} x - 12 = x + 3$

Combine $x$ and $\frac{1}{4}$ .

$- \frac{x}{4} - 12 = x + 3$

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$- \frac{x}{4} - 12 - x = 3$

To write $- x$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- \frac{x}{4} - x \cdot \frac{4}{4} - 12 = 3$

Combine $- x$ and $\frac{4}{4}$ .

$- \frac{x}{4} + \frac{- x \cdot 4}{4} - 12 = 3$

Combine the numerators over the common denominator.

$\frac{- x - x \cdot 4}{4} - 12 = 3$

Simplify each term.

Simplify the numerator.

Factor $x$ out of $- x - x \cdot 4$ .

Factor $x$ out of $- x$ .

$\frac{x \cdot - 1 - x \cdot 4}{4} - 12 = 3$

Factor $x$ out of $- x \cdot 4$ .

$\frac{x \cdot - 1 + x (- 1 \cdot 4)}{4} - 12 = 3$

Factor $x$ out of $x \cdot - 1 + x (- 1 \cdot 4)$ .

$\frac{x (- 1 - 1 \cdot 4)}{4} - 12 = 3$

Multiply $- 1$ by $4$ .

$\frac{x (- 1 - 4)}{4} - 12 = 3$

Subtract $4$ from $- 1$ .

$\frac{x \cdot - 5}{4} - 12 = 3$

Move $- 5$ to the left of $x$ .

$\frac{- 5 \cdot x}{4} - 12 = 3$

Move the negative in front of the fraction.

$- \frac{5 x}{4} - 12 = 3$

Move all terms not containing $x$ to the right side of the equation.

Add $12$ to both sides of the equation.

$- \frac{5 x}{4} = 3 + 12$

Add $3$ and $12$ .

$- \frac{5 x}{4} = 15$

Multiply both sides of the equation by $- \frac{4}{5}$ .

$- \frac{4}{5} (- \frac{5 x}{4}) = - \frac{4}{5} \cdot 15$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{4}{5} (- \frac{5 x}{4})$ .

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{4}{5}$ into the numerator.

$\frac{- 4}{5} (- \frac{5 x}{4}) = - \frac{4}{5} \cdot 15$

Move the leading negative in $- \frac{5 x}{4}$ into the numerator.

$\frac{- 4}{5} \cdot \frac{- 5 x}{4} = - \frac{4}{5} \cdot 15$

Factor $4$ out of $- 4$ .

$\frac{4 (- 1)}{5} \cdot \frac{- 5 x}{4} = - \frac{4}{5} \cdot 15$

Cancel the common factor.

$\frac{4 \cdot - 1}{5} \cdot \frac{- 5 x}{4} = - \frac{4}{5} \cdot 15$

Rewrite the expression.

$\frac{- 1}{5} (- 5 x) = - \frac{4}{5} \cdot 15$

Cancel the common factor of $5$ .

Factor $5$ out of $- 5 x$ .

$\frac{- 1}{5} (5 (- x)) = - \frac{4}{5} \cdot 15$

Cancel the common factor.

$\frac{- 1}{5} (5 (- x)) = - \frac{4}{5} \cdot 15$

Rewrite the expression.

$- - x = - \frac{4}{5} \cdot 15$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{4}{5} \cdot 15$

Multiply $x$ by $1$ .

$x = - \frac{4}{5} \cdot 15$

Simplify the right side.

Simplify $- \frac{4}{5} \cdot 15$ .

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{4}{5}$ into the numerator.

$x = \frac{- 4}{5} \cdot 15$

Factor $5$ out of $15$ .

$x = \frac{- 4}{5} \cdot (5 (3))$

Cancel the common factor.

$x = \frac{- 4}{5} \cdot (5 \cdot 3)$

Rewrite the expression.

$x = - 4 \cdot 3$

Multiply $- 4$ by $3$ .

$x = - 12$

Solve for x -1/4x-12=x+3

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