Solve for x 2x-(2(x+4)+4)=6x

$2 x - (2 (x + 4) + 4) = 6 x$

Step 1

Simplify $2 x - (2 (x + 4) + 4)$ .

Simplify each term.

Apply the distributive property.

$2 x - (2 x + 2 \cdot 4 + 4) = 6 x$

Multiply $2$ by $4$ .

$2 x - (2 x + 8 + 4) = 6 x$

Add $8$ and $4$ .

$2 x - (2 x + 12) = 6 x$

Apply the distributive property.

$2 x - (2 x) - 1 \cdot 12 = 6 x$

Multiply $2$ by $- 1$ .

$2 x - 2 x - 1 \cdot 12 = 6 x$

Multiply $- 1$ by $12$ .

$2 x - 2 x - 12 = 6 x$

Simplify by adding terms.

Subtract $2 x$ from $2 x$ .

$0 - 12 = 6 x$

Subtract $12$ from $0$ .

$- 12 = 6 x$

Step 2

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$6 x = - 12$

Step 3

Divide each term in $6 x = - 12$ by $6$ and simplify.

Divide each term in $6 x = - 12$ by $6$ .

$\frac{6 x}{6} = \frac{- 12}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{- 12}{6}$

Divide $x$ by $1$ .

$x = \frac{- 12}{6}$

Simplify the right side.

Divide $- 12$ by $6$ .

$x = - 2$