Solve for x (3x-6)/3+9=18

$\frac{3 x - 6}{3} + 9 = 18$

Step 1

Simplify $\frac{3 x - 6}{3} + 9$ .

Cancel the common factor of $3 x - 6$ and $3$ .

Factor $3$ out of $3 x$ .

$\frac{3 (x) - 6}{3} + 9 = 18$

Factor $3$ out of $- 6$ .

$\frac{3 (x) + 3 \cdot - 2}{3} + 9 = 18$

Factor $3$ out of $3 (x) + 3 (- 2)$ .

$\frac{3 (x - 2)}{3} + 9 = 18$

Cancel the common factors.

Factor $3$ out of $3$ .

$\frac{3 (x - 2)}{3 (1)} + 9 = 18$

Cancel the common factor.

$\frac{3 (x - 2)}{3 \cdot 1} + 9 = 18$

Rewrite the expression.

$\frac{x - 2}{1} + 9 = 18$

Divide $x - 2$ by $1$ .

$x - 2 + 9 = 18$

Add $- 2$ and $9$ .

$x + 7 = 18$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$x = 18 - 7$

Subtract $7$ from $18$ .

$x = 11$