Solve for x 4x+3(7+2(x-3))=83

$4 x + 3 (7 + 2 (x - 3)) = 83$

Simplify $4 x + 3 (7 + 2 (x - 3))$ .

Simplify each term.

Apply the distributive property.

$4 x + 3 (7 + 2 x + 2 \cdot - 3) = 83$

Multiply $2$ by $- 3$ .

$4 x + 3 (7 + 2 x - 6) = 83$

Subtract $6$ from $7$ .

$4 x + 3 (2 x + 1) = 83$

Apply the distributive property.

$4 x + 3 (2 x) + 3 \cdot 1 = 83$

Multiply $2$ by $3$ .

$4 x + 6 x + 3 \cdot 1 = 83$

Multiply $3$ by $1$ .

$4 x + 6 x + 3 = 83$

Add $4 x$ and $6 x$ .

$10 x + 3 = 83$

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$10 x = 83 - 3$

Subtract $3$ from $83$ .

$10 x = 80$

Divide each term in $10 x = 80$ by $10$ and simplify.

Divide each term in $10 x = 80$ by $10$ .

$\frac{10 x}{10} = \frac{80}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 x}{10} = \frac{80}{10}$

Divide $x$ by $1$ .

$x = \frac{80}{10}$

Simplify the right side.

Divide $80$ by $10$ .

$x = 8$