Solve for x x^2-5=-4

$x^{2} - 5 = - 4$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$x^{2} = - 4 + 5$

Add $- 4$ and $5$ .

$x^{2} = 1$

Step 2

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{1}$

Step 3

Any root of $1$ is $1$ .

$x = \pm 1$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 1$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 1$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 1, - 1$