Solve for y 12y+6=6(2y+1)

$12 y + 6 = 6 (2 y + 1)$

Step 1

Simplify $6 (2 y + 1)$ .

Rewrite.

$12 y + 6 = 0 + 0 + 6 (2 y + 1)$

Simplify by adding zeros.

$12 y + 6 = 6 (2 y + 1)$

Apply the distributive property.

$12 y + 6 = 6 (2 y) + 6 \cdot 1$

Multiply.

Multiply $2$ by $6$ .

$12 y + 6 = 12 y + 6 \cdot 1$

Multiply $6$ by $1$ .

$12 y + 6 = 12 y + 6$

Step 2

Move all terms containing $y$ to the left side of the equation.

Subtract $12 y$ from both sides of the equation.

$12 y + 6 - 12 y = 6$

Combine the opposite terms in $12 y + 6 - 12 y$ .

Subtract $12 y$ from $12 y$ .

$0 + 6 = 6$

Add $0$ and $6$ .

$6 = 6$

Step 3

Since $6 = 6$ , the equation will always be true for any value of $y$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$