Solve the Inequality for x -5+3x<-8(x+2)

$- 5 + 3 x < - 8 (x + 2)$

Simplify $- 8 (x + 2)$ .

Rewrite.

$- 5 + 3 x < 0 + 0 - 8 (x + 2)$

Simplify by adding zeros.

$- 5 + 3 x < - 8 (x + 2)$

Apply the distributive property.

$- 5 + 3 x < - 8 x - 8 \cdot 2$

Multiply $- 8$ by $2$ .

$- 5 + 3 x < - 8 x - 16$

Move all terms containing $x$ to the left side of the inequality.

Add $8 x$ to both sides of the inequality.

$- 5 + 3 x + 8 x < - 16$

Add $3 x$ and $8 x$ .

$- 5 + 11 x < - 16$

Move all terms not containing $x$ to the right side of the inequality.

Add $5$ to both sides of the inequality.

$11 x < - 16 + 5$

Add $- 16$ and $5$ .

$11 x < - 11$

Divide each term in $11 x < - 11$ by $11$ and simplify.

Divide each term in $11 x < - 11$ by $11$ .

$\frac{11 x}{11} < \frac{- 11}{11}$

Simplify the left side.

Cancel the common factor of $11$ .

Cancel the common factor.

$\frac{11 x}{11} < \frac{- 11}{11}$

Divide $x$ by $1$ .

$x < \frac{- 11}{11}$

Simplify the right side.

Divide $- 11$ by $11$ .

$x < - 1$

The result can be shown in multiple forms.

Inequality Form:

$x < - 1$

Interval Notation:

$(- \infty, - 1)$