Solve the Inequality for x 8(x+1)>7(x+2)

$8 (x + 1) > 7 (x + 2)$

Step 1

Simplify $8 (x + 1)$ .

Start simplifying.

$0 + 0 + 8 (x + 1) > 7 (x + 2)$

Simplify by adding zeros.

$8 (x + 1) > 7 (x + 2)$

Apply the distributive property.

$8 x + 8 \cdot 1 > 7 (x + 2)$

Multiply $8$ by $1$ .

$8 x + 8 > 7 (x + 2)$

Step 2

Simplify $7 (x + 2)$ .

Apply the distributive property.

$8 x + 8 > 7 x + 7 \cdot 2$

Multiply $7$ by $2$ .

$8 x + 8 > 7 x + 14$

Step 3

Move all terms containing $x$ to the left side of the inequality.

Subtract $7 x$ from both sides of the inequality.

$8 x + 8 - 7 x > 14$

Subtract $7 x$ from $8 x$ .

$x + 8 > 14$

Step 4

Move all terms not containing $x$ to the right side of the inequality.

Subtract $8$ from both sides of the inequality.

$x > 14 - 8$

Subtract $8$ from $14$ .

$x > 6$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$x > 6$

Interval Notation:

$(6, \infty)$