Solve Using a Matrix with Cramer's Rule x+5y=11 x-y=5

$x + 5 y = 11$ $x - y = 5$

Step 1

Represent the system of equations in matrix format.

$[\begin{array}{c} 1 & 5 \\ 1 & - 1 \end{array}] [\begin{array}{c} x \\ y \end{array}] = [\begin{array}{c} 11 \\ 5 \end{array}]$

Step 2

Find the determinant of $[\begin{array}{c} 1 & 5 \\ 1 & - 1 \end{array}]$ .

These are both valid notations for the determinant of a matrix.

$determinant [\begin{array}{c} 1 & 5 \\ 1 & - 1 \end{array}] = | \begin{array}{c} 1 & 5 \\ 1 & - 1 \end{array} |$

The determinant of a $2 \times 2$ matrix can be found using the formula $| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

$D = (1) (- 1) - 1 \cdot 5$

Simplify the determinant.

Simplify each term.

Multiply $- 1$ by $1$ .

$D = - 1 - 1 \cdot 5$

Multiply $- 1$ by $5$ .

$D = - 1 - 5$

Subtract $5$ from $- 1$ .

$D = - 6$

Step 3

Find the determinant of $[\begin{array}{c} 11 & 5 \\ 5 & - 1 \end{array}]$ .

These are both valid notations for the determinant of a matrix.

$determinant [\begin{array}{c} 11 & 5 \\ 5 & - 1 \end{array}] = | \begin{array}{c} 11 & 5 \\ 5 & - 1 \end{array} |$

The determinant of a $2 \times 2$ matrix can be found using the formula $| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

$D_{x} = (11) (- 1) - 5 \cdot 5$

Simplify the determinant.

Simplify each term.

Multiply $11$ by $- 1$ .

$D_{x} = - 11 - 5 \cdot 5$

Multiply $- 5$ by $5$ .

$D_{x} = - 11 - 25$

Subtract $25$ from $- 11$ .

$D_{x} = - 36$

Step 4

Find the determinant of $[\begin{array}{c} 1 & 11 \\ 1 & 5 \end{array}]$ .

These are both valid notations for the determinant of a matrix.

$determinant [\begin{array}{c} 1 & 11 \\ 1 & 5 \end{array}] = | \begin{array}{c} 1 & 11 \\ 1 & 5 \end{array} |$

The determinant of a $2 \times 2$ matrix can be found using the formula $| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

$D_{y} = (1) (5) - 1 \cdot 11$

Simplify the determinant.

Simplify each term.

Multiply $5$ by $1$ .

$D_{y} = 5 - 1 \cdot 11$

Multiply $- 1$ by $11$ .

$D_{y} = 5 - 11$

Subtract $11$ from $5$ .

$D_{y} = - 6$

Step 5

Find the value of $x$ by Cramer\'s Rule, which states that $x = \frac{D_{x}}{D}$ . In this case, $x = \frac{- 36}{- 6}$ .

Remove parentheses.

$x = \frac{- 36}{- 6}$

Divide $- 36$ by $- 6$ .

$x = 6$

Step 6

Find the value of $y$ by Cramer\'s Rule, which states that $y = \frac{D_{y}}{D}$ . In this case, $y = \frac{- 6}{- 6}$ .

Remove parentheses.

$y = \frac{- 6}{- 6}$

Divide $- 6$ by $- 6$ .

$y = 1$

Step 7

The solution to the system of equations using Cramer\'s Rule.

$x = 6, y = 1$

Step 8

Solve Using a Matrix with Cramer's Rule x+5y=11 x-y=5

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