Solve Using the Square Root Property x^2+8=28

$x^{2} + 8 = 28$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$x^{2} = 28 - 8$

Subtract $8$ from $28$ .

$x^{2} = 20$

Step 2

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{20}$

Step 3

Simplify $\pm \sqrt{20}$ .

Rewrite $20$ as $2^{2} \cdot 5$ .

Factor $4$ out of $20$ .

$x = \pm \sqrt{4 (5)}$

Rewrite $4$ as $2^{2}$ .

$x = \pm \sqrt{2^{2} \cdot 5}$

Pull terms out from under the radical.

$x = \pm 2 \sqrt{5}$

Step 4

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$x = 2 \sqrt{5}$

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 2 \sqrt{5}$

The complete solution is the result of both the positive and negative portions of the solution.

$x = 2 \sqrt{5}, - 2 \sqrt{5}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = 2 \sqrt{5}, - 2 \sqrt{5}$

Decimal Form:

$x = 4.47213595 \dots, - 4.47213595 \dots$