GCD of 468, 434, 642 Calculator

Given Input numbers are 468, 434, 642

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 468

List of positive integer divisors of 468 that divides 468 without a remainder.

1, 2, 3, 4, 6, 9, 12, 13, 18, 26, 36, 39, 52, 78, 117, 156, 234, 468

Divisors of 434

List of positive integer divisors of 434 that divides 434 without a remainder.

1, 2, 7, 14, 31, 62, 217, 434

Divisors of 642

List of positive integer divisors of 642 that divides 642 without a remainder.

1, 2, 3, 6, 107, 214, 321, 642

Greatest Common Divisior

We found the divisors of 468, 434, 642 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 468, 434, 642 is 2.

Therefore, GCD of numbers 468, 434, 642 is 2

Given Input Data is 468, 434, 642

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 468 is 2 x 2 x 3 x 3 x 13

Prime Factorization of 434 is 2 x 7 x 31

Prime Factorization of 642 is 2 x 3 x 107

Highest common occurrences in the given inputs are 2¹

Multiplying them we get the GCD as 2

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(468, 434) = 101556

GCD(468, 434) = ( 468 x 434 ) / 101556

GCD(468, 434) = 203112 / 101556

GCD(468, 434) = 2

Step2:

Here we consider the GCD from the above i.e. 2 as first number and the next as 642

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(2, 642) = 642

GCD(2, 642) = ( 2 x 642 ) / 642

GCD(2, 642) = 1284 / 642

GCD(2, 642) = 2

GCD of 468, 434, 642 is 2

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1. What is the GCD of 468, 434, 642?

GCD of 468, 434, 642 is 2

2. Where do I get the detailed procedure to find GCD of 468, 434, 642?

You can find a detailed procedure to find GCD of 468, 434, 642 on our page.

3. How to find GCD of 468, 434, 642 on a calculator?

You can find the GCD of 468, 434, 642 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.