GCD of 544, 558, 318 Calculator

Given Input numbers are 544, 558, 318

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 544

List of positive integer divisors of 544 that divides 544 without a remainder.

1, 2, 4, 8, 16, 17, 32, 34, 68, 136, 272, 544

Divisors of 558

List of positive integer divisors of 558 that divides 558 without a remainder.

1, 2, 3, 6, 9, 18, 31, 62, 93, 186, 279, 558

Divisors of 318

List of positive integer divisors of 318 that divides 318 without a remainder.

1, 2, 3, 6, 53, 106, 159, 318

Greatest Common Divisior

We found the divisors of 544, 558, 318 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 544, 558, 318 is 2.

Therefore, GCD of numbers 544, 558, 318 is 2

Given Input Data is 544, 558, 318

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 544 is 2 x 2 x 2 x 2 x 2 x 17

Prime Factorization of 558 is 2 x 3 x 3 x 31

Prime Factorization of 318 is 2 x 3 x 53

Highest common occurrences in the given inputs are 2¹

Multiplying them we get the GCD as 2

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(544, 558) = 151776

GCD(544, 558) = ( 544 x 558 ) / 151776

GCD(544, 558) = 303552 / 151776

GCD(544, 558) = 2

Step2:

Here we consider the GCD from the above i.e. 2 as first number and the next as 318

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(2, 318) = 318

GCD(2, 318) = ( 2 x 318 ) / 318

GCD(2, 318) = 636 / 318

GCD(2, 318) = 2

GCD of 544, 558, 318 is 2

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1. What is the GCD of 544, 558, 318?

GCD of 544, 558, 318 is 2

2. Where do I get the detailed procedure to find GCD of 544, 558, 318?

You can find a detailed procedure to find GCD of 544, 558, 318 on our page.

3. How to find GCD of 544, 558, 318 on a calculator?

You can find the GCD of 544, 558, 318 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.