GCD of 592, 928, 585 Calculator

Given Input numbers are 592, 928, 585

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 592

List of positive integer divisors of 592 that divides 592 without a remainder.

1, 2, 4, 8, 16, 37, 74, 148, 296, 592

Divisors of 928

List of positive integer divisors of 928 that divides 928 without a remainder.

1, 2, 4, 8, 16, 29, 32, 58, 116, 232, 464, 928

Divisors of 585

List of positive integer divisors of 585 that divides 585 without a remainder.

1, 3, 5, 9, 13, 15, 39, 45, 65, 117, 195, 585

Greatest Common Divisior

We found the divisors of 592, 928, 585 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 592, 928, 585 is 1.

Therefore, GCD of numbers 592, 928, 585 is 1

Given Input Data is 592, 928, 585

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 592 is 2 x 2 x 2 x 2 x 37

Prime Factorization of 928 is 2 x 2 x 2 x 2 x 2 x 29

Prime Factorization of 585 is 3 x 3 x 5 x 13

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(592, 928) = 34336

GCD(592, 928) = ( 592 x 928 ) / 34336

GCD(592, 928) = 549376 / 34336

GCD(592, 928) = 16

Step2:

Here we consider the GCD from the above i.e. 16 as first number and the next as 585

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(16, 585) = 9360

GCD(16, 585) = ( 16 x 585 ) / 9360

GCD(16, 585) = 9360 / 9360

GCD(16, 585) = 1

GCD of 592, 928, 585 is 1

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1. What is the GCD of 592, 928, 585?

GCD of 592, 928, 585 is 1

2. Where do I get the detailed procedure to find GCD of 592, 928, 585?

You can find a detailed procedure to find GCD of 592, 928, 585 on our page.

3. How to find GCD of 592, 928, 585 on a calculator?

You can find the GCD of 592, 928, 585 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.