GCD of 636, 528, 143 Calculator

Given Input numbers are 636, 528, 143

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 636

List of positive integer divisors of 636 that divides 636 without a remainder.

1, 2, 3, 4, 6, 12, 53, 106, 159, 212, 318, 636

Divisors of 528

List of positive integer divisors of 528 that divides 528 without a remainder.

1, 2, 3, 4, 6, 8, 11, 12, 16, 22, 24, 33, 44, 48, 66, 88, 132, 176, 264, 528

Divisors of 143

List of positive integer divisors of 143 that divides 143 without a remainder.

1, 11, 13, 143

Greatest Common Divisior

We found the divisors of 636, 528, 143 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 636, 528, 143 is 1.

Therefore, GCD of numbers 636, 528, 143 is 1

Given Input Data is 636, 528, 143

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 636 is 2 x 2 x 3 x 53

Prime Factorization of 528 is 2 x 2 x 2 x 2 x 3 x 11

Prime Factorization of 143 is 11 x 13

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(636, 528) = 27984

GCD(636, 528) = ( 636 x 528 ) / 27984

GCD(636, 528) = 335808 / 27984

GCD(636, 528) = 12

Step2:

Here we consider the GCD from the above i.e. 12 as first number and the next as 143

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(12, 143) = 1716

GCD(12, 143) = ( 12 x 143 ) / 1716

GCD(12, 143) = 1716 / 1716

GCD(12, 143) = 1

GCD of 636, 528, 143 is 1

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1. What is the GCD of 636, 528, 143?

GCD of 636, 528, 143 is 1

2. Where do I get the detailed procedure to find GCD of 636, 528, 143?

You can find a detailed procedure to find GCD of 636, 528, 143 on our page.

3. How to find GCD of 636, 528, 143 on a calculator?

You can find the GCD of 636, 528, 143 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.