GCD of 840, 825, 389 Calculator

Given Input numbers are 840, 825, 389

To find the GCD of numbers using factoring list out all the divisors of each number

Divisors of 840

List of positive integer divisors of 840 that divides 840 without a remainder.

1, 2, 3, 4, 5, 6, 7, 8, 10, 12, 14, 15, 20, 21, 24, 28, 30, 35, 40, 42, 56, 60, 70, 84, 105, 120, 140, 168, 210, 280, 420, 840

Divisors of 825

List of positive integer divisors of 825 that divides 825 without a remainder.

1, 3, 5, 11, 15, 25, 33, 55, 75, 165, 275, 825

Divisors of 389

List of positive integer divisors of 389 that divides 389 without a remainder.

1, 389

Greatest Common Divisior

We found the divisors of 840, 825, 389 . The biggest common divisior number is the GCD number.
So the Greatest Common Divisior 840, 825, 389 is 1.

Therefore, GCD of numbers 840, 825, 389 is 1

Given Input Data is 840, 825, 389

Make a list of Prime Factors of all the given numbers initially

Prime Factorization of 840 is 2 x 2 x 2 x 3 x 5 x 7

Prime Factorization of 825 is 3 x 5 x 5 x 11

Prime Factorization of 389 is 389

The above numbers do not have any common prime factor. So GCD is 1

Step1:

Let's calculate the GCD of first two numbers

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(840, 825) = 46200

GCD(840, 825) = ( 840 x 825 ) / 46200

GCD(840, 825) = 693000 / 46200

GCD(840, 825) = 15

Step2:

Here we consider the GCD from the above i.e. 15 as first number and the next as 389

The formula of GCD is GCD(a, b) = ( a x b) / LCM(a, b)

LCM(15, 389) = 5835

GCD(15, 389) = ( 15 x 389 ) / 5835

GCD(15, 389) = 5835 / 5835

GCD(15, 389) = 1

GCD of 840, 825, 389 is 1

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1. What is the GCD of 840, 825, 389?

GCD of 840, 825, 389 is 1

2. Where do I get the detailed procedure to find GCD of 840, 825, 389?

You can find a detailed procedure to find GCD of 840, 825, 389 on our page.

3. How to find GCD of 840, 825, 389 on a calculator?

You can find the GCD of 840, 825, 389 by simply giving the inputs separated by commas and click on the calculate button to avail the Greatest Common Divisor in less time.