Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 103, 435 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 103, 435 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 103, 435 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 103, 435 is 1.
HCF(103, 435) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 103, 435 is 1.
Step 1: Since 435 > 103, we apply the division lemma to 435 and 103, to get
435 = 103 x 4 + 23
Step 2: Since the reminder 103 ≠ 0, we apply division lemma to 23 and 103, to get
103 = 23 x 4 + 11
Step 3: We consider the new divisor 23 and the new remainder 11, and apply the division lemma to get
23 = 11 x 2 + 1
We consider the new divisor 11 and the new remainder 1, and apply the division lemma to get
11 = 1 x 11 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 103 and 435 is 1
Notice that 1 = HCF(11,1) = HCF(23,11) = HCF(103,23) = HCF(435,103) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 103, 435?
Answer: HCF of 103, 435 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 103, 435 using Euclid's Algorithm?
Answer: For arbitrary numbers 103, 435 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.