Highest Common Factor of 536, 512 using Euclid's algorithm
Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 536, 512 i.e. 8 the largest integer that leaves a remainder zero for all numbers.
HCF of 536, 512 is 8 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 536, 512 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 536, 512 is 8.
HCF(536, 512) = 8
HCF of 536, 512 using Euclid's algorithm
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 536, 512 is 8.
Highest Common Factor of 536,512 is 8
Step 1: Since 536 > 512, we apply the division lemma to 536 and 512, to get
536 = 512 x 1 + 24
Step 2: Since the reminder 512 ≠ 0, we apply division lemma to 24 and 512, to get
512 = 24 x 21 + 8
Step 3: We consider the new divisor 24 and the new remainder 8, and apply the division lemma to get
24 = 8 x 3 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 8, the HCF of 536 and 512 is 8
Notice that 8 = HCF(24,8) = HCF(512,24) = HCF(536,512) .
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Frequently Asked Questions on HCF of 536, 512 using Euclid's Algorithm
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 536, 512?
Answer: HCF of 536, 512 is 8 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 536, 512 using Euclid's Algorithm?
Answer: For arbitrary numbers 536, 512 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.