Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 582, 8201 i.e. 1 the largest integer that leaves a remainder zero for all numbers.
HCF of 582, 8201 is 1 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 582, 8201 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 582, 8201 is 1.
HCF(582, 8201) = 1
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 582, 8201 is 1.
Step 1: Since 8201 > 582, we apply the division lemma to 8201 and 582, to get
8201 = 582 x 14 + 53
Step 2: Since the reminder 582 ≠ 0, we apply division lemma to 53 and 582, to get
582 = 53 x 10 + 52
Step 3: We consider the new divisor 53 and the new remainder 52, and apply the division lemma to get
53 = 52 x 1 + 1
We consider the new divisor 52 and the new remainder 1, and apply the division lemma to get
52 = 1 x 52 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 582 and 8201 is 1
Notice that 1 = HCF(52,1) = HCF(53,52) = HCF(582,53) = HCF(8201,582) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 582, 8201?
Answer: HCF of 582, 8201 is 1 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 582, 8201 using Euclid's Algorithm?
Answer: For arbitrary numbers 582, 8201 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.