Created By : Jatin Gogia
Reviewed By : Rajasekhar Valipishetty
Last Updated : Apr 06, 2023
HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 612, 261 i.e. 9 the largest integer that leaves a remainder zero for all numbers.
HCF of 612, 261 is 9 the largest number which exactly divides all the numbers i.e. where the remainder is zero. Let us get into the working of this example.
Consider we have numbers 612, 261 and we need to find the HCF of these numbers. To do so, we need to choose the largest integer first and then as per Euclid's Division Lemma a = bq + r where 0 ≤ r ≤ b
Highest common factor (HCF) of 612, 261 is 9.
HCF(612, 261) = 9
Highest common factor or Highest common divisor (hcd) can be calculated by Euclid's algotithm.
Highest common factor (HCF) of 612, 261 is 9.
Step 1: Since 612 > 261, we apply the division lemma to 612 and 261, to get
612 = 261 x 2 + 90
Step 2: Since the reminder 261 ≠ 0, we apply division lemma to 90 and 261, to get
261 = 90 x 2 + 81
Step 3: We consider the new divisor 90 and the new remainder 81, and apply the division lemma to get
90 = 81 x 1 + 9
We consider the new divisor 81 and the new remainder 9, and apply the division lemma to get
81 = 9 x 9 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 9, the HCF of 612 and 261 is 9
Notice that 9 = HCF(81,9) = HCF(90,81) = HCF(261,90) = HCF(612,261) .
Here are some samples of HCF using Euclid's Algorithm calculations.
1. What is the Euclid division algorithm?
Answer: Euclid's Division Algorithm is a technique to compute the Highest Common Factor (HCF) of given positive integers.
2. what is the HCF of 612, 261?
Answer: HCF of 612, 261 is 9 the largest number that divides all the numbers leaving a remainder zero.
3. How to find HCF of 612, 261 using Euclid's Algorithm?
Answer: For arbitrary numbers 612, 261 apply Euclid’s Division Lemma in succession until you obtain a remainder zero. HCF is the remainder in the last but one step.