Divide (x^3-y^3)/(x-y)

$\frac{x^{3} - y^{3}}{x - y}$

Step 1

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = x$ and $b = y$ .

$\frac{(x - y) (x^{2} + x y + y^{2})}{x - y}$

Step 2

Cancel the common factor of $x - y$ .

Cancel the common factor.

$\frac{(x - y) (x^{2} + x y + y^{2})}{x - y}$

Divide $x^{2} + x y + y^{2}$ by $1$ .

$x^{2} + x y + y^{2}$

Divide (x^3-y^3)/(x-y)

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