Find the 6th Term 1 , 5 , 9 , 13 , 17

$1$ , $5$ , $9$ , $13$ , $17$

Step 1

This is an arithmetic sequence since there is a common difference between each term. In this case, adding $4$ to the previous term in the sequence gives the next term. In other words, $a_{n} = a_{1} + d (n - 1)$ .

Arithmetic Sequence: $d = 4$

Step 2

This is the formula of an arithmetic sequence.

$a_{n} = a_{1} + d (n - 1)$

Step 3

Substitute in the values of $a_{1} = 1$ and $d = 4$ .

$a_{n} = 1 + 4 (n - 1)$

Step 4

Simplify each term.

Apply the distributive property.

$a_{n} = 1 + 4 n + 4 \cdot - 1$

Multiply $4$ by $- 1$ .

$a_{n} = 1 + 4 n - 4$

Step 5

Subtract $4$ from $1$ .

$a_{n} = 4 n - 3$

Step 6

Substitute in the value of $n$ to find the $n$ th term.

$a_{6} = 4 (6) - 3$

Step 7

Multiply $4$ by $6$ .

$a_{6} = 24 - 3$

Step 8

Subtract $3$ from $24$ .

$a_{6} = 21$

Find the 6th Term 1 , 5 , 9 , 13 , 17

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