Find the Perfect Square Trinomial (w+3)^2

${(w + 3)}^{2}$

Step 1

Rewrite ${(w + 3)}^{2}$ as $(w + 3) (w + 3)$ .

$(w + 3) (w + 3)$

Step 2

Expand $(w + 3) (w + 3)$ using the FOIL Method.

Apply the distributive property.

$w (w + 3) + 3 (w + 3)$

Apply the distributive property.

$w \cdot w + w \cdot 3 + 3 (w + 3)$

Apply the distributive property.

$w \cdot w + w \cdot 3 + 3 w + 3 \cdot 3$

$w \cdot w + w \cdot 3 + 3 w + 3 \cdot 3$

Step 3

Simplify and combine like terms.

Simplify each term.

Multiply $w$ by $w$ .

$w^{2} + w \cdot 3 + 3 w + 3 \cdot 3$

Move $3$ to the left of $w$ .

$w^{2} + 3 \cdot w + 3 w + 3 \cdot 3$

Multiply $3$ by $3$ .

$w^{2} + 3 w + 3 w + 9$

$w^{2} + 3 w + 3 w + 9$

Add $3 w$ and $3 w$ .

$w^{2} + 6 w + 9$

$w^{2} + 6 w + 9$

Related Questions