Find the Position Vector (12,-7) , (-9,0)

$(12, - 7)$ , $(- 9, 0)$

Step 1

To find the position vector, subtract the initial point vector $P$ from the terminal point vector $Q$ .

$Q - P = (- 9 i + 0 j) - (12 i - 7 j)$

Step 2

Simplify each term.

Multiply $0$ by $j$ .

$- 9 i + 0 - (12 i - 7 j)$

Apply the distributive property.

$- 9 i + 0 - (12 i) - (- 7 j)$

Multiply $12$ by $- 1$ .

$- 9 i + 0 - 12 i - (- 7 j)$

Multiply $- 7$ by $- 1$ .

$- 9 i + 0 - 12 i + 7 j$

Step 3

Simplify by adding terms.

Add $- 9 i$ and $0$ .

$- 9 i - 12 i + 7 j$

Subtract $12 i$ from $- 9 i$ .

$- 21 i + 7 j$

Step 4