Find the Roots/Zeros Using the Rational Roots Test 2x^5+11x^4+18x^3+8x^2-4x-3

$2 x^{5} + 11 x^{4} + 18 x^{3} + 8 x^{2} - 4 x - 3$

Step 1

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 3$

$q = \pm 1, \pm 2$

Step 2

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm \frac{1}{2}, \pm 3, \pm \frac{3}{2}$

Step 3

Substitute the possible roots one by one into the polynomial to find the actual roots. Simplify to check if the value is $0$ , which means it is a root.

$2 {(- 1)}^{5} + 11 {(- 1)}^{4} + 18 {(- 1)}^{3} + 8 {(- 1)}^{2} - 4 \cdot - 1 - 3$

Step 4

Simplify the expression. In this case, the expression is equal to $0$ so $x = - 1$ is a root of the polynomial.

Simplify each term.

Raise $- 1$ to the power of $5$ .

$2 \cdot - 1 + 11 {(- 1)}^{4} + 18 {(- 1)}^{3} + 8 {(- 1)}^{2} - 4 \cdot - 1 - 3$

Multiply $2$ by $- 1$ .

$- 2 + 11 {(- 1)}^{4} + 18 {(- 1)}^{3} + 8 {(- 1)}^{2} - 4 \cdot - 1 - 3$

Raise $- 1$ to the power of $4$ .

$- 2 + 11 \cdot 1 + 18 {(- 1)}^{3} + 8 {(- 1)}^{2} - 4 \cdot - 1 - 3$

Multiply $11$ by $1$ .

$- 2 + 11 + 18 {(- 1)}^{3} + 8 {(- 1)}^{2} - 4 \cdot - 1 - 3$

Raise $- 1$ to the power of $3$ .

$- 2 + 11 + 18 \cdot - 1 + 8 {(- 1)}^{2} - 4 \cdot - 1 - 3$

Multiply $18$ by $- 1$ .

$- 2 + 11 - 18 + 8 {(- 1)}^{2} - 4 \cdot - 1 - 3$

Raise $- 1$ to the power of $2$ .

$- 2 + 11 - 18 + 8 \cdot 1 - 4 \cdot - 1 - 3$

Multiply $8$ by $1$ .

$- 2 + 11 - 18 + 8 - 4 \cdot - 1 - 3$

Multiply $- 4$ by $- 1$ .

$- 2 + 11 - 18 + 8 + 4 - 3$

Simplify by adding and subtracting.

Add $- 2$ and $11$ .

$9 - 18 + 8 + 4 - 3$

Subtract $18$ from $9$ .

$- 9 + 8 + 4 - 3$

Add $- 9$ and $8$ .

$- 1 + 4 - 3$

Add $- 1$ and $4$ .

$3 - 3$

Subtract $3$ from $3$ .

$0$

Step 5

Since $- 1$ is a known root, divide the polynomial by $x + 1$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$\frac{2 x^{5} + 11 x^{4} + 18 x^{3} + 8 x^{2} - 4 x - 3}{x + 1}$

Step 6

Next, find the roots of the remaining polynomial. The order of the polynomial has been reduced by $1$ .

Place the numbers representing the divisor and the dividend into a division-like configuration.

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0					\xa0

The first number in the dividend $(2)$ is put into the first position of the result area (below the horizontal line).

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0					\xa0
	$2$

Multiply the newest entry in the result $(2)$ by the divisor $(- 1)$ and place the result of $(- 2)$ under the next term in the dividend $(11)$ .

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$				\xa0
	$2$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$				\xa0
	$2$	$9$

Multiply the newest entry in the result $(9)$ by the divisor $(- 1)$ and place the result of $(- 9)$ under the next term in the dividend $(18)$ .

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$	$- 9$			\xa0
	$2$	$9$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$	$- 9$			\xa0
	$2$	$9$	$9$

Multiply the newest entry in the result $(9)$ by the divisor $(- 1)$ and place the result of $(- 9)$ under the next term in the dividend $(8)$ .

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$	$- 9$	$- 9$		\xa0
	$2$	$9$	$9$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$	$- 9$	$- 9$		\xa0
	$2$	$9$	$9$	$- 1$

Multiply the newest entry in the result $(- 1)$ by the divisor $(- 1)$ and place the result of $(1)$ under the next term in the dividend $(- 4)$ .

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$	$- 9$	$- 9$	$1$	\xa0
	$2$	$9$	$9$	$- 1$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$	$- 9$	$- 9$	$1$	\xa0
	$2$	$9$	$9$	$- 1$	$- 3$

Multiply the newest entry in the result $(- 3)$ by the divisor $(- 1)$ and place the result of $(3)$ under the next term in the dividend $(- 3)$ .

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$	$- 9$	$- 9$	$1$	$3$
	$2$	$9$	$9$	$- 1$	$- 3$

Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.

$- 1$	$2$	$11$	$18$	$8$	$- 4$	$- 3$
	\xa0	$- 2$	$- 9$	$- 9$	$1$	$3$
	$2$	$9$	$9$	$- 1$	$- 3$	$0$

All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.

$2 x^{4} + 9 x^{3} + 9 x^{2} + - 1 x - 3$

Simplify the quotient polynomial.

$2 x^{4} + 9 x^{3} + 9 x^{2} - x - 3$

Step 7

Solve the equation to find any remaining roots.

Factor the left side of the equation.

Regroup terms.

$9 x^{3} + 9 x^{2} + 2 x^{4} - x - 3 = 0$

Factor $9 x^{2}$ out of $9 x^{3} + 9 x^{2}$ .

Factor $9 x^{2}$ out of $9 x^{3}$ .

$9 x^{2} (x) + 9 x^{2} + 2 x^{4} - x - 3 = 0$

Factor $9 x^{2}$ out of $9 x^{2}$ .

$9 x^{2} (x) + 9 x^{2} (1) + 2 x^{4} - x - 3 = 0$

Factor $9 x^{2}$ out of $9 x^{2} (x) + 9 x^{2} (1)$ .

$9 x^{2} (x + 1) + 2 x^{4} - x - 3 = 0$

Factor $2 x^{4} - x - 3$ using the rational roots test.

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 3 q = \pm 1, \pm 2$

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm 0.5, \pm 3, \pm 1.5$

Substitute $- 1$ and simplify the expression. In this case, the expression is equal to $0$ so $- 1$ is a root of the polynomial.

Substitute $- 1$ into the polynomial.

$2 {(- 1)}^{4} - - 1 - 3$

Raise $- 1$ to the power of $4$ .

$2 \cdot 1 - - 1 - 3$

Multiply $2$ by $1$ .

$2 - - 1 - 3$

Multiply $- 1$ by $- 1$ .

$2 + 1 - 3$

Add $2$ and $1$ .

$3 - 3$

Subtract $3$ from $3$ .

$0$

Since $- 1$ is a known root, divide the polynomial by $x + 1$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$\frac{2 x^{4} - x - 3}{x + 1}$

Divide $2 x^{4} - x - 3$ by $x + 1$ .

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

Divide the highest order term in the dividend $2 x^{4}$ by the highest order term in divisor $x$ .

$2 x^{3}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

Multiply the new quotient term by the divisor.

$2 x^{3}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

The expression needs to be subtracted from the dividend, so change all the signs in $2 x^{4} + 2 x^{3}$

$2 x^{3}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$2 x^{3}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

Pull the next terms from the original dividend down into the current dividend.

$2 x^{3}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

Divide the highest order term in the dividend $- 2 x^{3}$ by the highest order term in divisor $x$ .

$2 x^{3}$

$2 x^{2}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

Multiply the new quotient term by the divisor.

$2 x^{3}$

$2 x^{2}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

The expression needs to be subtracted from the dividend, so change all the signs in $- 2 x^{3} - 2 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$2 x^{3}$

$2 x^{2}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

Pull the next terms from the original dividend down into the current dividend.

$2 x^{3}$

$2 x^{2}$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

Divide the highest order term in the dividend $2 x^{2}$ by the highest order term in divisor $x$ .

$2 x^{3}$

$2 x^{2}$

$2 x$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

Multiply the new quotient term by the divisor.

$2 x^{3}$

$2 x^{2}$

$2 x$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

$2 x^{2}$

$2 x$

The expression needs to be subtracted from the dividend, so change all the signs in $2 x^{2} + 2 x$

$2 x^{3}$

$2 x^{2}$

$2 x$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

$2 x^{2}$

$2 x$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$2 x^{3}$

$2 x^{2}$

$2 x$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

$2 x^{2}$

$2 x$

$3 x$

Pull the next terms from the original dividend down into the current dividend.

$2 x^{3}$

$2 x^{2}$

$2 x$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

$2 x^{2}$

$2 x$

$3 x$

$3$

Divide the highest order term in the dividend $- 3 x$ by the highest order term in divisor $x$ .

$2 x^{3}$

$2 x^{2}$

$2 x$

$3$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

$2 x^{2}$

$2 x$

$3 x$

$3$

Multiply the new quotient term by the divisor.

				$2 x^{3}$	-	$2 x^{2}$	+	$2 x$	-	$3$
$x$	+	$1$		$2 x^{4}$	+	$0 x^{3}$	+	$0 x^{2}$	-	$x$	-	$3$
			-	$2 x^{4}$	-	$2 x^{3}$
					-	$2 x^{3}$	+	$0 x^{2}$
					+	$2 x^{3}$	+	$2 x^{2}$
							+	$2 x^{2}$	-	$x$
							-	$2 x^{2}$	-	$2 x$
									-	$3 x$	-	$3$
									-	$3 x$	-	$3$

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 x - 3$

$2 x^{3}$

$2 x^{2}$

$2 x$

$3$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

$2 x^{2}$

$2 x$

$3 x$

$3$

$3 x$

$3$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$2 x^{3}$

$2 x^{2}$

$2 x$

$3$

$x$

$1$

$2 x^{4}$

$0 x^{3}$

$0 x^{2}$

$x$

$3$

$2 x^{4}$

$2 x^{3}$

$0 x^{2}$

$2 x^{3}$

$2 x^{2}$

$x$

$2 x^{2}$

$2 x$

$3 x$

$3$

$3 x$

$3$

$0$

Since the remander is $0$ , the final answer is the quotient.

$2 x^{3} - 2 x^{2} + 2 x - 3$

Write $2 x^{4} - x - 3$ as a set of factors.

$9 x^{2} (x + 1) + (x + 1) (2 x^{3} - 2 x^{2} + 2 x - 3) = 0$

Factor $x + 1$ out of $9 x^{2} (x + 1) + (x + 1) (2 x^{3} - 2 x^{2} + 2 x - 3)$ .

Factor $x + 1$ out of $9 x^{2} (x + 1)$ .

$(x + 1) (9 x^{2}) + (x + 1) (2 x^{3} - 2 x^{2} + 2 x - 3) = 0$

Factor $x + 1$ out of $(x + 1) (9 x^{2}) + (x + 1) (2 x^{3} - 2 x^{2} + 2 x - 3)$ .

$(x + 1) (9 x^{2} + 2 x^{3} - 2 x^{2} + 2 x - 3) = 0$

Subtract $2 x^{2}$ from $9 x^{2}$ .

$(x + 1) (2 x^{3} + 7 x^{2} + 2 x - 3) = 0$

Factor.

Rewrite $2 x^{3} + 7 x^{2} + 2 x - 3$ in a factored form.

Factor $2 x^{3} + 7 x^{2} + 2 x - 3$ using the rational roots test.

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 1, \pm 3 q = \pm 1, \pm 2$

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$\pm 1, \pm 0.5, \pm 3, \pm 1.5$

Substitute $- 1$ and simplify the expression. In this case, the expression is equal to $0$ so $- 1$ is a root of the polynomial.

Substitute $- 1$ into the polynomial.

$2 {(- 1)}^{3} + 7 {(- 1)}^{2} + 2 \cdot - 1 - 3$

Raise $- 1$ to the power of $3$ .

$2 \cdot - 1 + 7 {(- 1)}^{2} + 2 \cdot - 1 - 3$

Multiply $2$ by $- 1$ .

$- 2 + 7 {(- 1)}^{2} + 2 \cdot - 1 - 3$

Raise $- 1$ to the power of $2$ .

$- 2 + 7 \cdot 1 + 2 \cdot - 1 - 3$

Multiply $7$ by $1$ .

$- 2 + 7 + 2 \cdot - 1 - 3$

Add $- 2$ and $7$ .

$5 + 2 \cdot - 1 - 3$

Multiply $2$ by $- 1$ .

$5 - 2 - 3$

Subtract $2$ from $5$ .

$3 - 3$

Subtract $3$ from $3$ .

$0$

Since $- 1$ is a known root, divide the polynomial by $x + 1$ to find the quotient polynomial. This polynomial can then be used to find the remaining roots.

$\frac{2 x^{3} + 7 x^{2} + 2 x - 3}{x + 1}$

Divide $2 x^{3} + 7 x^{2} + 2 x - 3$ by $x + 1$ .

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$1$

$2 x^{3}$

$7 x^{2}$

$2 x$

$3$

Divide the highest order term in the dividend $2 x^{3}$ by the highest order term in divisor $x$ .

					$2 x^{2}$
	$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$

Multiply the new quotient term by the divisor.

				$2 x^{2}$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			+	$2 x^{3}$	+	$2 x^{2}$

The expression needs to be subtracted from the dividend, so change all the signs in $2 x^{3} + 2 x^{2}$

				$2 x^{2}$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$2 x^{2}$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$

Pull the next terms from the original dividend down into the current dividend.

				$2 x^{2}$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$

Divide the highest order term in the dividend $5 x^{2}$ by the highest order term in divisor $x$ .

				$2 x^{2}$	+	$5 x$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$

Multiply the new quotient term by the divisor.

				$2 x^{2}$	+	$5 x$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$
					+	$5 x^{2}$	+	$5 x$

The expression needs to be subtracted from the dividend, so change all the signs in $5 x^{2} + 5 x$

				$2 x^{2}$	+	$5 x$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$
					-	$5 x^{2}$	-	$5 x$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$2 x^{2}$	+	$5 x$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$
					-	$5 x^{2}$	-	$5 x$
							-	$3 x$

Pull the next terms from the original dividend down into the current dividend.

				$2 x^{2}$	+	$5 x$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$
					-	$5 x^{2}$	-	$5 x$
							-	$3 x$	-	$3$

Divide the highest order term in the dividend $- 3 x$ by the highest order term in divisor $x$ .

				$2 x^{2}$	+	$5 x$	-	$3$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$
					-	$5 x^{2}$	-	$5 x$
							-	$3 x$	-	$3$

Multiply the new quotient term by the divisor.

				$2 x^{2}$	+	$5 x$	-	$3$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$
					-	$5 x^{2}$	-	$5 x$
							-	$3 x$	-	$3$
							-	$3 x$	-	$3$

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 x - 3$

				$2 x^{2}$	+	$5 x$	-	$3$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$
					-	$5 x^{2}$	-	$5 x$
							-	$3 x$	-	$3$
							+	$3 x$	+	$3$

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$2 x^{2}$	+	$5 x$	-	$3$
$x$	+	$1$		$2 x^{3}$	+	$7 x^{2}$	+	$2 x$	-	$3$
			-	$2 x^{3}$	-	$2 x^{2}$
					+	$5 x^{2}$	+	$2 x$
					-	$5 x^{2}$	-	$5 x$
							-	$3 x$	-	$3$
							+	$3 x$	+	$3$
										$0$

Since the remander is $0$ , the final answer is the quotient.

$2 x^{2} + 5 x - 3$

Write $2 x^{3} + 7 x^{2} + 2 x - 3$ as a set of factors.

$(x + 1) ((x + 1) (2 x^{2} + 5 x - 3)) = 0$

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot - 3 = - 6$ and whose sum is $b = 5$ .

Factor $5$ out of $5 x$ .

$(x + 1) ((x + 1) (2 x^{2} + 5 (x) - 3)) = 0$

Rewrite $5$ as $- 1$ plus $6$

$(x + 1) ((x + 1) (2 x^{2} + (- 1 + 6) x - 3)) = 0$

Apply the distributive property.

$(x + 1) ((x + 1) (2 x^{2} - 1 x + 6 x - 3)) = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(x + 1) ((x + 1) ((2 x^{2} - 1 x) + 6 x - 3)) = 0$

Factor out the greatest common factor (GCF) from each group.

$(x + 1) ((x + 1) (x (2 x - 1) + 3 (2 x - 1))) = 0$

Factor the polynomial by factoring out the greatest common factor, $2 x - 1$ .

$(x + 1) ((x + 1) ((2 x - 1) (x + 3))) = 0$

Remove unnecessary parentheses.

$(x + 1) ((x + 1) (2 x - 1) (x + 3)) = 0$

Remove unnecessary parentheses.

$(x + 1) (x + 1) (2 x - 1) (x + 3) = 0$

Combine exponents.

Raise $x + 1$ to the power of $1$ .

$(x + 1) (x + 1) (2 x - 1) (x + 3) = 0$

Raise $x + 1$ to the power of $1$ .

$(x + 1) (x + 1) (2 x - 1) (x + 3) = 0$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

${(x + 1)}^{1 + 1} (2 x - 1) (x + 3) = 0$

Add $1$ and $1$ .

${(x + 1)}^{2} (2 x - 1) (x + 3) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

${(x + 1)}^{2} = 0$

$2 x - 1 = 0$

$x + 3 = 0$

Set ${(x + 1)}^{2}$ equal to $0$ and solve for $x$ .

Set ${(x + 1)}^{2}$ equal to $0$ .

${(x + 1)}^{2} = 0$

Solve ${(x + 1)}^{2} = 0$ for $x$ .

Set the $x + 1$ equal to $0$ .

$x + 1 = 0$

Subtract $1$ from both sides of the equation.

$x = - 1$

Set $2 x - 1$ equal to $0$ and solve for $x$ .

Set $2 x - 1$ equal to $0$ .

$2 x - 1 = 0$

Solve $2 x - 1 = 0$ for $x$ .

Add $1$ to both sides of the equation.

$2 x = 1$

Divide each term in $2 x = 1$ by $2$ and simplify.

Divide each term in $2 x = 1$ by $2$ .

$\frac{2 x}{2} = \frac{1}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{1}{2}$

Divide $x$ by $1$ .

$x = \frac{1}{2}$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

Subtract $3$ from both sides of the equation.

$x = - 3$

The final solution is all the values that make ${(x + 1)}^{2} (2 x - 1) (x + 3) = 0$ true.

$x = - 1, \frac{1}{2}, - 3$

Step 8

The polynomial can be written as a set of linear factors.

$(x + 1) (x - \frac{1}{2}) (x + 3)$

Step 9

These are the roots (zeros) of the polynomial $2 x^{5} + 11 x^{4} + 18 x^{3} + 8 x^{2} - 4 x - 3$ .

$x = - 1, \frac{1}{2}, - 3$

Step 10

Find the Roots/Zeros Using the Rational Roots Test 2x^5+11x^4+18x^3+8x^2-4x-3

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