Find the Slope and y-intercept (3,-8) , (6,-4)

$(3, - 8)$ , $(6, - 4)$

Step 1

Find the value of the slope.

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 4 - (- 8)}{6 - (3)}$

Simplify.

Simplify the numerator.

Multiply $- 1$ by $- 8$ .

$m = \frac{- 4 + 8}{6 - (3)}$

Add $- 4$ and $8$ .

$m = \frac{4}{6 - (3)}$

Simplify the denominator.

Multiply $- 1$ by $3$ .

$m = \frac{4}{6 - 3}$

Subtract $3$ from $6$ .

$m = \frac{4}{3}$

Step 2

Find the value of the y-intercept.

Substitute the value of $m$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (\frac{4}{3}) x + b$

Substitute the value of $x$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (\frac{4}{3}) \cdot (3) + b$

Substitute the value of $y$ into the slope-intercept form of the equation, $y = m x + b$ .

$- 8 = (\frac{4}{3}) \cdot (3) + b$

Rewrite the equation as $(\frac{4}{3}) \cdot (3) + b = - 8$ .

$(\frac{4}{3}) \cdot (3) + b = - 8$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{4}{3} \cdot 3 + b = - 8$

Rewrite the expression.

$4 + b = - 8$

Move all terms not containing $b$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$b = - 8 - 4$

Subtract $4$ from $- 8$ .

$b = - 12$

Step 3

List the slope and y-intercept.

Slope: $\frac{4}{3}$

y-intercept: $(0, - 12)$

Step 4

Find the Slope and y-intercept (3,-8) , (6,-4)

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