Find the x and y Intercepts f(x)=(x+2)/(2x+6)

$f (x) = \frac{x + 2}{2 x + 6}$

Find the x-intercepts.

To find the x-intercept(s), substitute in $0$ for $y$ and solve for $x$ .

$0 = \frac{x + 2}{2 x + 6}$

Solve the equation.

Set the numerator equal to zero.

$x + 2 = 0$

Subtract $2$ from both sides of the equation.

$x = - 2$

x-intercept(s) in point form.

x-intercept(s): $(- 2, 0)$

Find the y-intercepts.

To find the y-intercept(s), substitute in $0$ for $x$ and solve for $y$ .

$y = \frac{(0) + 2}{2 (0) + 6}$

Solve the equation.

Remove parentheses.

$y = \frac{0 + 2}{2 (0) + 6}$

Remove parentheses.

$y = \frac{(0) + 2}{2 (0) + 6}$

Simplify $\frac{(0) + 2}{2 (0) + 6}$ .

Cancel the common factor of $(0) + 2$ and $2 (0) + 6$ .

Factor $2$ out of $0$ .

$y = \frac{2 (0) + 2}{2 (0) + 6}$

Factor $2$ out of $2$ .

$y = \frac{2 \cdot 0 + 2 \cdot 1}{2 (0) + 6}$

Factor $2$ out of $2 \cdot 0 + 2 \cdot 1$ .

$y = \frac{2 \cdot (0 + 1)}{2 (0) + 6}$

Cancel the common factors.

Factor $2$ out of $6$ .

$y = \frac{2 \cdot (0 + 1)}{2 (0) + 2 (3)}$

Factor $2$ out of $2 (0) + 2 (3)$ .

$y = \frac{2 \cdot (0 + 1)}{2 (0 + 3)}$

Cancel the common factor.

$y = \frac{2 \cdot (0 + 1)}{2 (0 + 3)}$

Rewrite the expression.

$y = \frac{0 + 1}{0 + 3}$

Simplify by adding zeros.

Add $0$ and $1$ .

$y = \frac{1}{0 + 3}$

Add $0$ and $3$ .

$y = \frac{1}{3}$

y-intercept(s) in point form.

y-intercept(s): $(0, \frac{1}{3})$

List the intersections.

x-intercept(s): $(- 2, 0)$

y-intercept(s): $(0, \frac{1}{3})$

Find the x and y Intercepts f(x)=(x+2)/(2x+6)

Related Questions

Support LCMGCF.com by disabling your adblocker.