Graph -2(x-3y)=12

$- 2 (x - 3 y) = 12$

Solve for $y$ .

Add $2 x$ to both sides of the equation.

$6 y = 12 + 2 x$

Divide each term in $6 y = 12 + 2 x$ by $6$ and simplify.

Divide each term in $6 y = 12 + 2 x$ by $6$ .

$\frac{6 y}{6} = \frac{12}{6} + \frac{2 x}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 y}{6} = \frac{12}{6} + \frac{2 x}{6}$

Divide $y$ by $1$ .

$y = \frac{12}{6} + \frac{2 x}{6}$

Simplify the right side.

Simplify each term.

Divide $12$ by $6$ .

$y = 2 + \frac{2 x}{6}$

Cancel the common factor of $2$ and $6$ .

Factor $2$ out of $2 x$ .

$y = 2 + \frac{2 (x)}{6}$

Cancel the common factors.

Factor $2$ out of $6$ .

$y = 2 + \frac{2 x}{2 \cdot 3}$

Cancel the common factor.

$y = 2 + \frac{2 x}{2 \cdot 3}$

Rewrite the expression.

$y = 2 + \frac{x}{3}$

Rewrite in slope-intercept form.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Reorder $2$ and $\frac{x}{3}$ .

$y = \frac{x}{3} + 2$

Reorder terms.

$y = \frac{1}{3} x + 2$

Use the slope-intercept form to find the slope and y-intercept.

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = \frac{1}{3}$

$b = 2$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $\frac{1}{3}$

y-intercept: $(0, 2)$

Slope: $\frac{1}{3}$

y-intercept: $(0, 2)$

Any line can be graphed using two points. Select two $x$ values, and plug them into the equation to find the corresponding $y$ values.

Write in $y = m x + b$ form.

Reorder $2$ and $\frac{x}{3}$ .

$y = \frac{x}{3} + 2$

Reorder terms.

$y = \frac{1}{3} x + 2$

Create a table of the $x$ and $y$ values.

$\begin{array}{c} x & y \\ 0 & 2 \\ 3 & 3 \end{array}$

Graph the line using the slope and the y-intercept, or the points.

Slope: $\frac{1}{3}$

y-intercept: $(0, 2)$

$\begin{array}{c} x & y \\ 0 & 2 \\ 3 & 3 \end{array}$

Graph -2(x-3y)=12

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