Graph x+y>1 -x-y<-3

$x + y > 1$ $- x - y < - 3$

Graph $x + y > 1$ .

Write in $y = m x + b$ form.

Subtract $x$ from both sides of the inequality.

$y > 1 - x$

Rearrange terms.

$y > - x + 1$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 1$

$b = 1$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 1$

y-intercept: $(0, 1)$

Slope: $- 1$

y-intercept: $(0, 1)$

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $- x + 1$ .

$y > - x + 1$

Graph $- x - y < - 3$ .

Write in $y = m x + b$ form.

Solve for $y$ .

Add $x$ to both sides of the inequality.

$- y < - 3 + x$

Divide each term in $- y < - 3 + x$ by $- 1$ and simplify.

Divide each term in $- y < - 3 + x$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} > \frac{- 3}{- 1} + \frac{x}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} > \frac{- 3}{- 1} + \frac{x}{- 1}$

Divide $y$ by $1$ .

$y > \frac{- 3}{- 1} + \frac{x}{- 1}$

Simplify the right side.

Simplify each term.

Divide $- 3$ by $- 1$ .

$y > 3 + \frac{x}{- 1}$

Move the negative one from the denominator of $\frac{x}{- 1}$ .

$y > 3 - 1 \cdot x$

Rewrite $- 1 \cdot x$ as $- x$ .

$y > 3 - x$

Rearrange terms.

$y > - x + 3$

Use the slope-intercept form to find the slope and y-intercept.

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Find the values of $m$ and $b$ using the form $y = m x + b$ .

$m = - 1$

$b = 3$

The slope of the line is the value of $m$ , and the y-intercept is the value of $b$ .

Slope: $- 1$

y-intercept: $(0, 3)$

Slope: $- 1$

y-intercept: $(0, 3)$

Graph a dashed line, then shade the area above the boundary line since $y$ is greater than $- x + 3$ .

$y > - x + 3$

Plot each graph on the same coordinate system.

$x + y > 1$

$- x - y < - 3$

Graph x+y>1 -x-y<-3

Related Questions

Support LCMGCF.com by disabling your adblocker.